Okay so- I picked the yellow one and I don’t know if I’m correct?

So just read yhe picture please

const2013 [10]

The correct answer is B). 6

Radius of inscribed circle of triangle HJK is 6 unit

Step-by-step explanation:

As shown in figure,

The triangle HJK has In-circle or inscribed circle of radius PL(or PM or PN)

Since, PL and PM is radius of same in-circle,

PL = PM

Given that PL=3x+4 and PM =6x-14

3x+4=6x-14

3x=18

x=6

Thus, The correct answer is B). 6

6 0

3 years ago

If x=2 and y =0 what is the value of x²-y(x-y)-1

dimulka [17.4K]

Answer:

3

Step-by-step explanation:

x = 2

y = 0

plug in values

$2^2$ - 0(2-0)-1

4- 0(2)-1

4-0-1

4-1

3

5 0

2 years ago

What is the slope of the line that passes through (-4, 6) and (-6, 20)?

Hatshy [7]

Answer:

-7

Step-by-step explanation:

Since we have two points, we can use the slope formula

m = ( y2-y1)/(x2-x1)

= ( 20-6)/(-6- -4)

= ( 20-6)/ ( -6+4)

= 14/-2

= -7

3 0

3 years ago

-6-5

Dmitry [639]

Answer: A

Step-by-step explanation:

Following the first two steps of the sequence of transformations,

$A(-4,-2) \longrightarrow (-2,-1) \longrightarrow (-2,1)$

We need to map this onto D(1,1), which involves a translation 3 units right.

4 0

2 years ago

|1/2b-8|=|1/4b-1|<br> b=____ and ____

Deffense [45]

Answer:

b = 12 and 28

Step-by-step explanation:

The absolute value equation |1/2b-8| = |1/4b-1| resolves to a piecewise linear function with three pieces. There are two solutions.

<h3>Domains</h3>

The absolute value function on the left has a turning point where its value is zero:

1/2b -8 = 0

b -16 = 0

b = 16

The absolute value function on the right has a turning point where its value is zero:

1/4b -1 = 0

b -4 = 0

b = 4

For b > 16, both absolute value functions are identity functions. In this domain, the equation is ...

1/2b -8 = 1/4b -1

For 4 < b < 16, the function on the left negates its argument, so the equation in this domain is ...

-(1/2b -8) = 1/4b -1

For b < 4, both functions negate their arguments, so the equation in this domain is ...

-(1/2b -8) = -(1/4b -1)

For the purpose of finding the value of b, this is effectively identical to the equation for b > 16. (The value of b does not change if we multiply both sides of the equation by -1.)

<h3>Solutions</h3>

<u>Domain b < 4 ∪ 16 < b</u>

1/2b -8 = 1/4b -1

2b -32 = b -4 . . . . . . . . multiply by 4

b = 28 . . . . . . . . . . . . add 32-b to both sides

This solution is in the domain of the equation, so is one of the solutions to the original equation.

<u>Domain 4 < b < 16</u>

-(1/2b -8) = 1/4b -1 . . . . equation in this domain

-2b +32 = b -4 . . . . . . multiply by 4

36 = 3b . . . . . . . . . . . add 2b+4 to both sides

12 = b . . . . . . . . . . . . divide by 3

This solution is in the domain of the equation, so is the other solution to the original equation.

<h3>Graph</h3>

For the purposes of the graph, we have define the function g(b) to be the difference of the two absolute value functions. The solutions are found where g(x) = 0, the x-intercepts. The graph shows those to be ...

b = 12 and b = 28

__

<em>Additional comment</em>

Defining g(b) = |1/2b-8| -|1/4b-1|, we can rewrite it as ...

$g(b)=\begin{cases}7-\dfrac{1}{4}b&\text{for }b < 4\\-\dfrac{3}{4}b+9&\text{for }4\le b < 16\\\dfrac{1}{4}b-7&\text{for }16\le b\end{cases}$

Then the solutions are the values of b that make g(b) = 0.

4 0

2 years ago