The diameter of the new rubber ball, to the nearest foot, must be D = 4.0 ft (in the case of the maximum cost).
<h3>
How to find the diameter of the ball?</h3>
Remember that for a sphere of diameter D, the surface area is:
A = 4*pi*(D/2)^2
In this case, the cost is $0.02 per square foot, and the company wants to expend (at maximum) $1 per ball, so first we need to solve:
$0.02*A = $1
A = $1/$0.02 = 50
So the surface of the ball must be 50 square feet.
Then we solve:
50ft^2 = 4*3.14*(D/2)^2
D = 2*√(50 ft^2/(4*3.14)) = 4.0 ft
If you want to learn more about spheres, you can read:
brainly.com/question/10171109
The Answer For This Is 5^3<span>√10 - 1/2</span>
Answer:
(5^4)^2
Step-by-step explanation:
Answer:
x = 73/4
Step-by-step explanation:
Solve for x:
12 x - 39 = 180
Add 39 to both sides:
12 x + (39 - 39) = 39 + 180
39 - 39 = 0:
12 x = 180 + 39
180 + 39 = 219:
12 x = 219
Divide both sides of 12 x = 219 by 12:
(12 x)/12 = 219/12
12/12 = 1:
x = 219/12
The gcd of 219 and 12 is 3, so 219/12 = (3×73)/(3×4) = 3/3×73/4 = 73/4:
Answer: x = 73/4
Answer:
48∛9 ft²
Step-by-step explanation:
Data
The area of the rectangular region is computed as follows:
area = length * width
area = 4 ∛24 * 6 ∛3
area = 4*6* ∛(24*3)
area = 24 * ∛(2³*3*3)
area = 24 * 2∛9
area = 48∛9 ft²
