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butalik [34]
2 years ago
14

I need to have this done by tonight and I don’t know what to put

Mathematics
1 answer:
a_sh-v [17]2 years ago
5 0

Answer:

A. Option 1

Sign up cost = 0

1 Month = 125

2 Months = 150

3 Months = 175

4 Months = 200

Step-by-step explanation:

For every option simply write what the starting cost is in the top box for every option. Then multiply the monthly cost by how many months for each box and then add the starting cost. The result of the multiplication and addition will be what you put in each box.

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51 m^2

Step-by-step explanation:

Area = 11(3) + 6(3) = 51 m^2

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Is –22 + 9 positive or negative?
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The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

7 0
2 years ago
Arithmetic Series Algebra 2
gtnhenbr [62]

The 6 terms of the series are

... 15, 14, 13, 12, 11, 10

The sum of them is 75.

_____

You could make use of the formula for the sum of the terms, or you could work out the sum from the given expression. It is easier just to list the terms and and them up.

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