Answer:
3/4
Step-by-step explanation:
Add the like terms (varibles) on both sides if their the same
The correct answer is going to be7
Answer:
The particle changes its direction 2 times within the time -3<t<3
Step-by-step explanation:
The particle is moving only in a single dimension (x-axis), and whenever the particle changes its direction it also means that it's velocity while changing the direction will be zero.
Hence,
v(t) = 0
but since we're not concerned with the actual values of t when v(t)=0, we'll only consider how many times does the particle changes its direction.
for that we'll simply plot the curve using half-steps from -3 to 3.
t, v(t)
-3, 115
-2.5, 23.9375
-2, -16
-1.5, -25.0625
-1, -19
-0.5, -9.0625
0, -2
0.5, -0.0625
1, -1
1.5, 1.9375
2, 20
2.5, 68.9375
3, 169
What we need to check is at what points does the sign of v(t) values change (because only between those points will v(t) cross the x-axis, hence it's value would've crossed 0)
so there are two points!
between the intervals t = [-2.5,2] and [1,1.5]
so there are two points where the particle changes its directions and those points lie somewhere between these two aforementioned intervals.
Answer:
y = 7/5x + 4
Step-by-step explanation:
use the slope from the equation -5/7 and take the negative reciprocal to get the perpendicular slope = 7/5. Then use the equation y=mx+b. Plug in x and y from the point given and the new slope and solve for b.
(-3) = (7/5)(-5) + b, (-3) = -7 + b, add 7 to both sides. b = 4. Rewrite the equation now to be y = 7/5x + 4
