Ask question

Ask question

All categories

3 years ago

5

After running for two minutes, a jaguar has gone 180 feet. After five minutes, it has run 450 feet. Write an equation to represe

nt the total distance, y, the jaguar runs in x minutes.A.) y = 45x B.)y = 90x C.)y = 180x D.)y = 450x

1 answer:

patriot [66]3 years ago

8 0

Answer:

B) y=90x

Step-by-step explanation:

The jaguar runs 90 feet in one minute.

You might be interested in

Help (the answer isn't the 2nd one my friend did this test and chose that and got it wrong please )

Artyom0805 [142]

Answer: 4 and 3/5

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

3 years ago

Read 2 more answers

The equation for the graph of A is

inna [77]

Answer:

Where is the graph? pls show graph so we can answer :)

4 0

2 years ago

Read 2 more answers

Carefully review the research matrix presented below. If this is a within subjects design, how many total participants will be u

frozen [14]

Answer:

c. 45

Step-by-step explanation:

there are 15 participant in each category, and there are 3 categories, so total participants = 15 * 3

= 45

Hope this helps, and please mark me brainliest if it does!

5 0

3 years ago

Idk this is supper hard

vlabodo [156]

Answer:

The equation of the line is: y = x + 4

Step-by-step explanation:

When we are given two points passing through a line, we can find the equation of the line by using two - point form.

Two - point form: $\frac{\textbf{y - y}_\textbf{1}}{\textbf{y}_{\textbf{2}} \textbf{-} \textbf{y}_{\textbf{1}}} = \frac{{\textbf{x - x}_\textbf{1}}}{\textbf{x}_{\textbf{2}} \textbf{-} \textbf{x}_{\textbf{1}} }$

where $(x_1, y_1) \hspace{3mm} \& \hspace{3mm} (x_2, y_2)$ are the points passing through the line.

Here, let us take two points (can be any two):

$(x _1, y_1) = (1, 5)$ and

$(x_2, y_2) = (5, 9)$

Therefore, we have:

$\frac{y - 5}{9 - 5} = \frac{x - 1}{5 - 1}$

$\iff \frac{y - 5}{4} = \frac{x - 1}{4}$

$\iff y - 5 = x - 1$

$\implies y = x - 1 + 5$

$\implies y = \textbf{x + 4}$ which is the required answer.

4 0

3 years ago