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Zepler [3.9K]
3 years ago
7

How do you do the bottom 4? Thanks!

Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0
Alrightie! So we are trying to isolate independent variables! WOO HOO! 

So for a.) y = mx + b which is the point-slope formula... do this :)

y = mx + b
y - b = mx + b - b
y - b = mx 

\frac{y-b}{x} =  \frac{mx}{x}
m =  \frac{y-b}{x}

b.) follow the same way I did above, but instead of dividing x, divide by m.

c.)  I = prt which is the equation for interest. 
divide each side by pr.

d.) This one is like a and b. So lemme show ya.

A - p = prt
\frac{A-p}{pr} =  \frac{t}{pr}
t = \frac{A-p}{pr}
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2 years ago
Help me solve it please
snow_tiger [21]

Answer:

\fbox{\begin{minipage}{5.8 em}x =5.97 cm\end{minipage}}

Step-by-step explanation:

(1) As definition, the area (A) of a circle is calculated by:

A = \pi x r^{2} with r is radius of circle.

(2) The relation between radius (r) and diameter (d_{1}) of a circle is:

d_{1} = 2 x r

(3) Applying the Pythagorean theorem for a square with sides of length x,

the relation between side x and diagonal d_{2} is:

x^{2} +x^{2}  = d^{2} \\or\\2x^{2} = d^{2}

=> The diagonal (d_{2}) of that square is calculated by:

d_{2} = x\sqrt{2}

(4) The square fits exactly inside a circle, with each of its vertices being on the circumference of the circle.

Applying the theorem of inscribed angle in a circle, the measure of arc BD is twice as the measure of inscribed angle BAD.

In other words, the measure of arc AC = 2 x 90 = 180 deg, or half of circle.

It means that the diagonal BD is coincide with a diameter of circle.

=> d_{1} = d_{2}

or 2 x r = x\sqrt{2}

or r = x\frac{\sqrt{2} }{2}

Substitute r back into original formula used for calculating the area of circle:

=> A = \pi x (x\frac{\sqrt{2}}{2})^{2} = \pi x \frac{x^{2}}{2}

=> x^{2}  = A x \frac{2}{\pi }

=> x = \sqrt{A} x \sqrt{\frac{2}{\pi } } = \sqrt{56} x \sqrt{\frac{2}{\pi } } = 5.97 cm

Hope this helps!

:)

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Answer:

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Step-by-step explanation:

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*********

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