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3 years ago

10

How many rubber bands does Brendan have

1 answer:

ArbitrLikvidat [17]3 years ago

4 0

88+r

Plug in a random number for r like 1

Brendan has 1 more rubber bands than Keenan

If Keenan has 88 then Brendan will have 1 more than that

So 88+r

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Please help me as soon as possible

Alex777 [14]

Answer:

I think the choose (B)

5x/x + 3/x

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3 years ago

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A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u

OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

$\displaystyle\frac{8000\pi\sqrt{2}}{3}$

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

$x^2+y^2=15^2\to y=\sqrt{225-x^2}$

Then we set the integral for the volume by using shell method:

$\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx$

That can be solved by substitution:

$u=225-x^2\to du=-2xdx$

The limits of integration also change:

For x=5: $u=225-5^2=200$

For x=15: $u=225-15^2=0$

So the integral becomes:

$\displaystyle -\int_{200}^{0}\pi \sqrt{u}du$

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

$\displaystyle \int_{0}^{200}\pi u^{1/2}du$

Then applying the basic rule we get:

$\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}$

Since that is just half of the solid, we multiply by 2 to get the complete volume:

$\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}$

$=\displaystyle\frac{8000\pi\sqrt{2}}{3}$

5 0

4 years ago

Which ordered pair describes a point with a location in the first quadrant of a coordinate plane?

Serga [27]

Answer:

(3, 2)

Step-by-step explanation:

7 0

3 years ago

Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6

kirill [66]

Answer:

Option (a) is correct.

The system of equation becomes

$y=12x^3-5x\\\\ y=2x^2+x+6$

Step-by-step explanation:

Given : Equation $12x^3-5x=2x^2+x+6$

We have to construct a system of equations that can be used to find the roots of the equation $12x^3-5x=2x^2+x+6$

Consider the given equation $12x^3-5x=2x^2+x+6$

To construct a system of equation put both sides of the given equation equal to a same variable.

Let the variable be "y", Then the equation $12x^3-5x=2x^2+x+6$

becomes,

$12x^3-5x=y=2x^2+x+6$

Thus, The system of equation becomes

$y=12x^3-5x\\\\ y=2x^2+x+6$

Option (a) is correct.

8 0

3 years ago

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Twice a number plus 6 times the number is 72

ExtremeBDS [4]

Answer:

9

Step-by-step explanation:

Let the no be x

By the conditions given ,

2x + 6x = 72

8x = 72

x = 72/8

x = 9

therefore the no is 9

6 0

3 years ago

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