Answer:
The volume of base was required for the titration is 13,53mL
Explanation:
In a titration of an acid (HX) with a base (YOH), the reaction of neutralization is:
HX + YOH → YX + H₂O
In the burette you are adding base until all HX reacts. The addition of base is in volume.
If in the beginnig, the volume that you read of base is 2,94mL and at the endpoint you read a volume of 16,47mL. The volume you spent in the titration that is the same volume of base you required for the titration is:
16,47mL - 2,94mL = <em>13,53mL</em>
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I hope it helps!
A. Removal of a water molecule between each two units
There are three perfect squares in a standard die; 1, 2, 4. If there is two standard dies, then the probability of getting a perfect square is 1/3 x 1/3 = 1/9.
There are 4 numbers less than 5 in a standard die, making it 1/4 x 1/4=1/16.
So what’s the question? I’m confused
It's D because I know bcz I'm smart 8 times 8 is 60-nart