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Nadusha1986 [10]
3 years ago
8

What is the percent by mass of oxygen fe2o3 (formula mass= 160)?

Chemistry
1 answer:
GarryVolchara [31]3 years ago
5 0
30% should be the percentage of oxygen if the total mass of fe2o3 is 160.
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Reactants are carbon dioxide and water, the products are glucose and oxygen. Don't know for sure what the yield is represented with, so, I can't help you with that.

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An electrolytic cell is based upon a nonspontaneous reaction; the Eocell for the reaction is _____.
Likurg_2 [28]

In an electrochemical cell in which the oxidation reaction is nonspontaneous  the oxidation will not occur spontaneously at the anode and the reduction will not be spontaneous at the cathode.  And according to the law for the calculation of the voltage potential of the electrochemical cell (Ecell):

Ecell = Eox. - Ere.  where (Eox. is the potential of the oxidation at the anode and Ere. is the potential of the reduction at the cathode). The standard potential for an electrolytic cell is negative, because of the Ere. which is greater than Eox.

The answer is : less than zero.

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3 years ago
What does a gamma ray primarily consist of?
damaskus [11]
Answer is D

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NEED HELP ASAP WILL GIVE BRAINLYEST Organisms that are made up of prokaryotic cells are NOT ____________. Multicellular All of t
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Explanation:

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6 0
2 years ago
PLEASE I NEED HELP ASAP!!!!
miv72 [106K]

The percent yield of the calcium hydroxide is 84.5%.

<h3>What is stoichiometry?</h3>

Stoichiometry enables us to obtain the mass of a substance form the equation of the reaction.

The equation of the reaction is;

CaCO3 + 2HCl -----> CaCl2 + CO2 + H2O

Number of moles of X = 40.0 grams/100 g/mol = 0.4 moles

Number of moles of HCl = 850/1000 * 1 M = 0.85 moles

If 1 mole of CaCO3 reacts with 2 moles of HCl

0.4 moles of  CaCO3 reacts with  0.4 moles  * 2 moles/1 mole

= 0.8 moles of HCl

Hence X is the limiting reactant.

The reaction is 1:1 then the amount of CO2  produced is 0.4 moles

Mass of CO2 = 0.4 CO2 * 44 g/mol = 17.6 g

2) The reaction equation is; 2NaOH + CaCO3 --->  Ca(OH)2 + Na2CO3

Number of moles of X = 25.0 grams/100 g/mol =  0.25 moles

Number of moles of NaOH= 40/1000 L * 2 M = 0.08 moles

If 1 mole of X reacts with 2 moles of NaOH

0.25 moles  reacts with   0.25 moles   * 2 moles /1 mole

= 0.5 moles

NaOH is the limiting reactant

2 moles of NaOH produces 1 mole of CO2

0.08 moles of NaOH produces 0.08 moles * 1 mole/2 moles

= 0.04 moles of CO2

Theoretical yield of CO2 =  0.04 moles of CO2 * 74 g/mol = 2.96  g

Percent yield = 2.5 g/ 2.96  g * 100

= 84.5%

Learn ore about percent yield:brainly.com/question/17042787

#SPJ1

5 0
2 years ago
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