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fgiga [73]
2 years ago
10

How do you write 4,083/1000 as a percentage?

Mathematics
2 answers:
nika2105 [10]2 years ago
8 0

Answer:

408.3%

Step-by-step explanation:

Zinaida [17]2 years ago
4 0
The answer is 408.3%
You might be interested in
Sum of interior angles of a convex 14-gon
just olya [345]

Answer: 2160°

Step-by-step explanation:

The sum of angles in a polygon is represented by the formula:

Sum = (n - 2) x 180° where n is the number of sides in the polygon

In this case, the complex polygon has 14 sides (n = 14)

So, (14 - 2) x 180°

= 12 x 180°

= 2160°

Thus, the sum of interior angles of a convex 14-gon is 2160°

3 0
3 years ago
Look at pic and solve
Brilliant_brown [7]

Answer:

Yes it can be solved.

Step-by-step explanation:

I did this stuff in like 4th grade lollll

5 0
2 years ago
an apple and a banana cost $2.10 the apple is $2.00 more than the banana how much does the banana cost
Korolek [52]
$2.10 - $2 = $0.10

The banana cost 10 cents.
8 0
2 years ago
Is the number -9/20 a rational number
Maslowich
I believe it is a rational number
5 0
2 years ago
b) If parametric equations of a flow line are x = x(t), y = y(t), explain why these functions satisfy the differential equations
sineoko [7]

Answer:

The equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1.

Step-by-step explanation:

The pathline equation for a vector field is given by F(x,y) = xî - yj

The velocity vector field for the streamline of the flow is given by

V(x, y) = (dx/dt)î + (dy/dt)j

From the question, it is given that

(dx/dt) = x

(dy/dt) = -y

Hence, the velocity vector field for the streamline of the flow in question is

V(x, y) = xî - yj

which coincides with the pathline vector field of the flow.

The only time the pathline and streamline vector field coincide and have the same equation is when the flow is a steady state flow.

That is, the properties of the fluid flowing isn't changing with time!

Hence, this flow is a steady state flow!

We're told to solve the differential equation.

(dx/dt) = x

(dy/dt) = -y

but

(dy/dx) = (dy/dt) × (dt/dx)

(dy/dx) = -y/x

(dy/y) = -(dx/x)

∫(dy/y) = -∫ (dx/x)

In y = - In x + c

where c is the constant of integration

In y + In x = c

In (xy) = c

Inserting the values of (x, y) given in the question,

In (-1 × -1) = c

In 1 = c

0 = c

c = 0

In y + In x = 0

In (yx) = 0

xy = e⁰ = 1

xy = 1

So, the equation of the the flow line that passes through the point (x, y) = (−1, −1) is

In y + In x = 0 or in another form, xy = 1

Hope this Helps!!!

4 0
3 years ago
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