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forsale [732]
3 years ago
8

Is 0.088 greater than, less than or equal to 0.88

Mathematics
1 answer:
pogonyaev3 years ago
8 0
It's less than 
0.88 = 0.880
0.088 = 0.088
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I am having trouble with this problem....
Alexeev081 [22]

There 2 angles are corresponding angles, in which the angle measurements would have the same degree.

Set the two angles equal to each other, and solve for x.

7x - 1 = 8x - 14

Isolate the x. Subtract 8x from both sides, and add 1 to both sides

7x (-8x) - 1 (+1) = -14 (+1)

7x - 8x = -14 + 1

-x = -13

Isolate the x. Divide -1 from both sides

(-x)/-1 = (-13)/-1

x = -13/-1

x = 13

13 is your answer for x.

~

4 0
3 years ago
1 to 8 plz plz plz help me
e-lub [12.9K]

Answer:

1-8 = -7

Step-by-step explanation:

1 - 8

1 0 -1 -2 -3 -4 -5 -6 -7

4 0
2 years ago
I am stuck on the before last question of this maths exam. I need reasoning for each answer and that is what I can't seem to get
sleet_krkn [62]

Answer:

write this:

<BAC=x(alternate segment theorem)

<ABC=x

triangle ABC has 2 equal angles so it is an isosceles triangle.

7 0
3 years ago
Check all that apply. If csc =13/5 , then:
nirvana33 [79]

Answer:

The answer are the options B and C

sin(x)=\frac{5}{13}

tan(x)=\frac{5}{12}

Step-by-step explanation:

we know that

csc(x)=\frac{1}{sin(x)}

In this problem we have

csc(x)=\frac{13}{5}

substitute

\frac{13}{5}=\frac{1}{sin(x)}

solve for sin(x)

sin(x)=\frac{5}{13}

cos^{2}(x)+sin^{2}(x)=1

substitute the value of sin(x) and solve for cos(x)

cos^{2}(x)+(\frac{5}{13})^{2}=1

cos^{2}(x)=1-(\frac{5}{13})^{2}

cos^{2}(x)=(\frac{13^{2}-5^{2}}{13^{2}})

cos^{2}(x)=(\frac{144}{13^{2}})

cos^{2}(x)=(\frac{12^{2}}{13^{2}})

cos(x)=(\frac{12}{13})

The function tangent is equal to

tan(x)=\frac{sin(x)}{cos(x)}

substitute the values

tan(x)=\frac{(5/13)}{(12/13)}=5/12

8 0
3 years ago
Read 2 more answers
If you are rolling a 6-sided number cube, what is the probability that you will roll a number less than 3?
weeeeeb [17]
2 out of 6 (3 out of 6 if 3 itself is included)
8 0
3 years ago
Read 2 more answers
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