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lakkis [162]
2 years ago
7

C&A Museum has three million visitors per year. Each visitor spends an averageof 1 hour in the museum. What is the average n

umber of visitors in the museum on agiven day if the museum is open 300 days a year from 9 a.m. to 5 p.m.?
Mathematics
1 answer:
Alona [7]2 years ago
8 0

Answer:

1250 visitors per day

Step-by-step explanation:

Number of visitors per year = 3,000,000

Number of days open per year = 300

Number of hours = 9a.m to 5pm = 8 hours

Number of visitors per hour :

Number of visitors per year / (number of days per year * number of hours per day)

3000000 / (300 * 8)

3000000 / 2400

= 1250 visitors per day

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Using the Pythagorean theorem a^2 +b^2 = c^2, where a and b are the sides of a triangle and c is the hypotenuse.

BA and AC are sides and BC is the hypotenuse.

we have 23^2 + b^2 = 45^2

529 + b^2 = 2025

b^2 = 2025 - 529

b^2 = 1496

b = sqrt(1496)

b = 38.68 = 38.7

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4 0
2 years ago
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As a river guide on the gauja river, antra earned $55 per passenger and a $25 tip. if she earned $410 altogether, how many passe
Ket [755]

410 - 25 = 386

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3 years ago
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Sonny has $75 to spend. The purchase he wants to make requires$93. If he borrows the extra money that he needs, how much does he
lidiya [134]
All you gotta do is subtract both of the numbers to get how much you need.

93 - 75 = 18

We can double check to see if it's right by using addition

18 + 75 = 93

Sonny needs to borrow 18$ to meet his required amount :D
7 0
3 years ago
Find the length of the third side. If necessary, write in simplest radical form.
melisa1 [442]

\text{Apply Pythagorean theorem,}\\\\~~~~~~~~\text{Hypotenuse}^2=\text{Base}^2 + \text{Perpendicular}^2\\\\\implies 9^2 = \text{Base}^2 + \left(2\sqrt{14} \right)^2\\\\\implies 81 = \text{Base}^2 + 56\\\\\implies \text{Base}^2 = 81-56\\\\\implies \text{Base}^2 = 25\\\\\implies \text{Base} = \sqrt{25}\\\\\implies \text{Base} = 5\\\\\text{The length of the third side is 5 units.}

4 0
1 year ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
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