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nasty-shy [4]
3 years ago
5

3.

Mathematics
2 answers:
lutik1710 [3]3 years ago
6 0

Answer:

First quartile: 17

Second quartile: 24.5

Third quartile: 32

ollegr [7]3 years ago
4 0

Answer:

Lower quartile (xL): 16.75

Median (xm): 24.5

Upper quartile (xU): 33.5

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Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble
Anettt [7]
A=bh
1056=32<span>×b
</span>÷32  ÷32
3<span>3=h
The height is </span>3<span>3 inches.</span>
8 0
2 years ago
Read 2 more answers
PLEASE HELP ME SEE IF MY ANSWERS ARE CORRECT!!!!!!!
Lena [83]
So first one
'how many solutions does 2x-y=-5 and 2x+y=5 have?'
add and get
2x-y-5
plus
2x+y=5

equals
2x+2x+y-y=5-5
4x=0
x=0 always
solve for y
4(0)+y=5
y=5
the solution is (0,5)
only <u>ONE </u>solution






one way is to subsitute
just remember that it is in (x,y) form so
the pont (1,2) means that 1 solution is x=1 and y=2 so subsitute and find that
the first one is the answer you are correct





just look at the graph
the solution is the intersection
it seems to be at a point that is 3 units to the right and -6 units up (6 units down)
so the solution is (3,-6)
yo are corect








subsitution
y=y
therefor
the answe ris (-4,-14) if you did the math correctly











#8 is correct

# 9 is correct




# 10 the answe ris bananas=0.40 pears=0.60


the  last one you got it wrong, remember to check your answer to the graph for commonsense
then answer is (-2,5) and (1,2)
8 0
3 years ago
Suppose y varies directly as x², and y = 160 when x = 4. Find y when x = 6.
labwork [276]

<u>Finding the constant of proportionality</u> :

  • y = kx²
  • 160 = k(4)²
  • k = 10

<u>Finding y when x = 6</u> :

  • y = 10(6)²
  • y = 10(36)
  • y = 360

The value of y is <u>360</u> when x = 6.

7 0
1 year ago
Help me please ❤️❤️❤️❤️
melomori [17]

In a quadratic function, f(x)= ax^2+bx+c the leading coefficient is a, i.e. the coefficient of x^2, and the constant term is c, i.e. the coefficient without any power of x.

So, if you want leading coefficient 2 and constant term -3, your function needs to be like

f(x)=2x^2+bx-3

for any value of b. Among your options:

  • The first is not a quadratic (it starts with x^3)
  • The second has leading term -3 and constant term 2
  • The third is not a quadratic (same as the first)
  • The last is correct.
4 0
3 years ago
Match the graph
AVprozaik [17]
It is c because i believe so
8 0
1 year ago
Read 2 more answers
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