The series converges to 1/(1-9x) for -1/9<x<1/9
Given the series is ∑ 
We have to find the values of x for which the series converges.
We know,
∑ 
converges to (a) / (1-r) if r < 1
Otherwise the series will diverge.
Here, ∑ 
is a geometric series with |r| = | 9x |
And it converges for |9x| < 1
Hence, the given series gets converge for -1/9<x<1/9
And geometric series converges to a/(1-r)
Here, a = 1 and r = 9x
Therefore, a/(1-r) = 1/(1-9x)
Hence, the given series converges to 1/1-9x for -1/9<x<1/9
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Answer:
y=-1/2x+2
the y-intercept is at 2 and the slope is -1/2
meaning the y coordinates with move down 1 while the x coordinates will move 2 in a positive (right) direction
Answer:
4/12 or 1/3
Step-by-step explanation:
Answer:
0.67
Step-by-step explanation:
To solve this we are going to use this lovely equation
P%•X=Y
Y is our end product
X in this case is 45
and P% is our percent
Now let's multiply 4% which becomes .004 by 45 and we get 1.8 which since there isn't 1.8 in American currency that becomes $1.80
We do the same process with the 2.5
0.025•45=1.125
Again not in the American currency so we will round 5 up and now we have $1.13
Now we subtract 1.80-1.13 which gets us 0.67 cents.
Hope I was helpful,
Your friendly neighborhood struggling student
Toodles
When thinking about reinforcement, always remember that the end result is to try to increase the behavior, whereas punishment procedures are used to decrease behavior. For positive reinforcement, try to think of it as adding something positive in order to increase a response.
