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n200080 [17]
3 years ago
13

Find the sum.Use fraction strips to help 1/6 + 1/3 + 1/6 ​

Mathematics
1 answer:
victus00 [196]3 years ago
5 0

Answer:

\frac{2}{3}

Step-by-step explanation:

Since \frac{1}{6} and \frac{1}{6} have the same denominators, we add them first. We then add \frac{1}{3} to the result.

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The domain of f(x) is {-2,0,1}. If f(x) = 4x+1, what is the range?
bekas [8.4K]

The range of function is: {-7,1,5}

Step-by-step explanation:

Given function is:

f(x) = 4x+1

Also the domain:  {-2,0,1}

In order to find the range,, we have to put the domains values in the function

So,

Putting x = -2

=4(-2)+1\\= -8+1\\=-7

Putting x = 0

=4(0)+1\\= 0+1\\=1

Putting x = 1

=4(1)+1\\= 4+1\\= 5

Hence,

The range of function is: {-7,1,5}

Keywords: domain, range

Learn more about functions at:

  • brainly.com/question/10879401
  • brainly.com/question/10940255

#LearnwithBrainly

5 0
3 years ago
50 POINTS!!!<br><br> Find the area of the segment of circle C shown in the diagram above.
pochemuha
  • B.the area =9.76u^2
  • the area of the sector =1/2 x r^2 x (the angle in radian -sin(the same angle in degrees)
6 0
4 years ago
Read 2 more answers
Remove the parentheses and simplify the expression 3(2x+3)-6
astra-53 [7]
First multiple everything in the parentheses by
3
3 (2x+3)-6=
3(2x)+3(3)-6=
6x+9-6
then add together like terms
6x+9-6=
6x+3
so 6x+3 is your answer
7 0
3 years ago
Read 2 more answers
If X=2 find the value of q in the equation 3x-4= X+q​
Svetradugi [14.3K]

Answer:

3x - 4 = x + q \\ 3(2) - 4 - (2) = q \\ 6 - 4 - 2 = q \\ 0 = q \:  \: or \:  \: q = 0

7 0
3 years ago
Read 2 more answers
The height, h, in metres, of a rocket t seconds after it is launched is approximately modelled by the quadratic relation h = 80t
8_murik_8 [283]

Answer: 5 s

Step-by-step explanation:

Given

Height of the rocket can be modelled as h=80-16t^2

Rocket will land on earth when it's height becomes 0

\Rightarrow 80t-16t^2=0\\\Rightarrow t(80-16t)=0\\\\\Rightarrow t=0\ \text{or}\ t=\dfrac{80}{16}=5\ s

Neglecting 0 value

Thus, rocket remains in air for 5 s.

3 0
3 years ago
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