The average density of Earth is 5.44 g/cm³.
<em>Mass</em>
Mass = 5.974 × 10²⁴ kg = 5.974 × 10²⁷ g
<em>Volume
</em>
<em>d</em> = 2<em>r</em> = 1.28 × 10⁴ km
<em>r</em> = 6.40 × 10³ km × (10³m/1 km) × (10² cm/1 m) = 6.40 × 10⁸ cm
<em>V</em> = ⁴/₃π<em>r</em>³ = ⁴/₃π × (6.40 × 10⁸ cm)³ = 1.098 × 10²⁷ cm³
<em>Density
</em>
Density = mass/volume = (5.974 × 10²⁷ g)/(1.098 × 10²⁷ cm³) = 5.44 g/cm³
111. 6 grams of oxygen is needed
To determine the ratio of atoms present in this ionic compound, first write the charges of the ions, and swap the charges to determine the subscripts of the atoms.
Fe^+2 S^-2
FeS.
This refers to the ratio as 1 Fe ion for 1 S ion.
The answer is C potential energy to kinetic energy.