What would be the new volume if the pressure on 600 L is increased from 90.0 kPa to 150 kPa?
1 answer:
Answer:
new Volume of gas=360L
Explanation:
Assume that given gas follow the ideality nature of gas
Assuming that temperature is constant;
P1 and V1 are the initial parameter of gas
and p2 and V2 are the parameter after increasing the pressure
according to boyle 's law pressure is inversly proportional to the volume at constant temperature.
given value of volume and gas
P1=90kPa
V1=600L
P2=150kPa
V2=?
After putting all values we get;
V2=360L
new Volume of gas=360L
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Answer:
Attached below
Explanation:
Free energy of mixing = ΔGmix = Gf - Gi
attached below is the required derivation of the
<u>a) Molar Gibbs energy of mixing</u>
ΔGmix = Gf - Gi
hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )
<u>b) molar excess Gibbs energy of mixing</u>
Ni = chemical potential of gas
fi = Fugacity
N°i = Chemical potential of gas when Fugacity = 1
ΔG = RT In ( a2 / a1 )
