This dissociation occur because:
O had to bond with H due to the Hydrogen bonding rule, which will form OH~ (Hydroxide).
K is more attracted to Hydroxide than Cl, so it will depart Cl and bond with OH~.
that leaves a H and a Cl, which one has a positive charge and the other has a negative, so they will bond and form Hydrochloric Acid.
The rate of effusion of ammonia (NH₃) in the same apparatus is 63.3 cm/min
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>How to determine the rate of ammonia (NH₃) </h3>
- Rate of HCl (R₁) = 43.2 cm/min
- Molar mass of HCl (M₁) = 1 + 35.5 = 36.5 g/mol
- Molar mass of NH₃ (M₂) = 14 + (3×1) = 17 g/mol
R₁/R₂ = √(M₂/M₁)
43.2 / R₂ = √(17 / 36.5)
Cross multiply
43.2 = R₂ × √(17 / 36.5)
Divide both side by √(17 / 36.5)
R₂ = 43.2 / √(17 / 36.5)
R₂ = 63.3 cm/min
Thus, the rate of effusion of ammonia is 63.3 cm/min
Learn more about Graham's law of diffusion:
brainly.com/question/14004529
Lets name one gas sample as A and other gas sample as B.
we can apply ideal gas law equation for both samples
PV = nRT
P - Pressure of A = Pressure of B
V - volume of A = volume of B
n - number of molecules of both A and B being equal is equivalent to number of moles of A = number of moles of B
R - universal gas constant
Tᵃ - temperature of A
Tᵇ - temperature of B
for gas A
PV = nRTᵃ --1)
for gas B
PV = nRTᵇ ---2)
when we divide both equations
1 = Tᵃ / Tᵇ
Tᵃ = Tᵇ
both temperatures are equal
temperature in Celsius + 273 = temperature in Kelvin
therefore 0 °C = 273 K
the correct answer is
A)
<span>The first gas sample has a temperature of 273 K, and the second gas sample has a temperature of 0 </span>°<span>C</span>
