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gizmo_the_mogwai [7]
3 years ago
10

I had four numbers: 12, 8, 4, and ????? However, I remember that their average was 11. Please, help me to remember the number th

at I forgot!!! The number that our old math teacher forgot is
Mathematics
2 answers:
Anestetic [448]3 years ago
5 0

Answer:

The number was 20

Step-by-step explanation:

As the average is 11 and the numbers are 4, so the total sum of numbers will be 11X4=44. now the sum of three numbers are (20+8+4)=24. So the last number will be= (44-24)=20. :)

dolphi86 [110]3 years ago
5 0

Answer:

20, 12,8,4 average out to 11

Step-by-step explanation:

omni average calculator on google will help :)

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Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
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The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

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k=\frac{0.693}{t_{1/2}}

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Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
3 years ago
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