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Lina20 [59]
3 years ago
11

Classify the number −25.

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

Answer:

integer

Step-by-step explanation:

..................

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Do you have a picture to your problem ?
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What is the point of intercection of lines y=x and y=2x+1
12345 [234]

Answer:

(-1, -1)

Step-by-step explanation:

Let's set these two equations equal to each other to solve the system:

x = 2x + 1

Solving for x, we get x = -1

Plug this value of x back into any of the two equations to get y: y = 2 * (-1) + 1 = -1.

Thus, the point of intersection is (-1, -1).

Hope this helps!

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3 years ago
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Pre-Calc: Find all the zeros of the function.
uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Read more about polynomial at

brainly.com/question/17517586

#SPJ1

5 0
1 year ago
A machine produces 75 widgets an hour. How many widgets does it produce in 6 minutes
inn [45]
75/60 is 1.25 and 1.25 times 6 is 7.5 but you can't produce a half widget so it is just 7
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3 years ago
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I need help with both questions...
NikAS [45]

Answer:

17. a)

Step-by-step explanation:

17.

f(x) =x/2, then f(x-3)=(x-3)/2

x=3, f(x-3)=f(3-3)=f(0)=0 (values in table)

f(x-3)+3=0+3=3

18.

f(x) =x/2

f(x-2) for x=5 is f(5-2)=f(3)=3/2

f(x-2)+5=f(3)+5=3/2+5=3/2+10/2=13/2

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3 years ago
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