Answer:
5.90
Explanation:
Initial moles of CH3COO- = 10.0/1000 x 0.75 = 0.0075 mol
Moles of HCl added = 5.0/1000 x 0.10 = 0.0005 mol
CH3COO- + HCl => CH3COOH + Cl-
Moles of CH3COO- left = 0.0075 - 0.0005 = 0.007 mol
Moles of CH3COOH formed = moles of HCl added = 0.0005 mol
pH = pKa + log([CH3COO-]/[CH3COOH])
= -log Ka + log(moles of CH3COO-/moles of CH3COOH)
= -log(1.78 x 10^(-5)) + log(0.007/0.0005)
= 5.90
Answer: 1.1 moles H2O
Explanation: It looks like the equation is already balanced for you, so the first step will be to convert 144.1 grams of HNO3 to moles. To do this find the molar mass, and use to to do your conversion.Using the numbers provided for mass, this is the equation:1(1.0) + 1(14) + 3(16) = 1 + 14 + 48 = 63 g/mol144.1 g HNO3 x 1 mol HNO3 = 2.287 mol HNO3 63 g HNO3Now that you know how many moles of HNO3 you're starting with, use the ratio of moles in the equation to find the moles of H2O produced. The coefficient of HNO3 is 8, and H2O is 42.287 mol HNO3 x 4 mol H2O = 1.144 mol H2O 8 mol HNO3
Answer:
In these two-letter symbols, the first letter is always capitalized and the second is always lowercased.
PH3
Also known as phosphine
Answer:
Answer: Chemical change; Chemical property of heat of combustion
Explanation:
A physical change is defined as a change in which there is alteration in shape, size etc. No new substance gets formed in these reactions.
Explanation:
