Answer:
The answer is <em>G</em><em>a</em><em>m</em><em>m</em><em>a</em><em> </em><em>r</em><em>a</em><em>y</em><em> </em><em>.</em>
(Correct me if I am wrong)
Answer:
44.28 grams.
Explanation:
Let us write the balanced reaction:

As per balanced equation, six moles of fluorine gas will give four moles of PF₃.
The mass of PF₃ required = 120 g
The molar mass of PF₃ = 88g/mol
Moles of PF₃ required =
The moles of fluorine gas required = 
the mass of fluorine gas required = moles X molar mass = 0.91x38 = 34.58g
Now this much mass will be required if the reaction is of 100% yield
But as given that the yield of reaction is only 78.1%
The mass of fluorine required = 
Well you would use Charles V1/T1 = V2/T2. Look at the picture for more explanation
The formula of a compound formed between nitrogen (N) and barium (Ba) is BARIUM NITRIDE Ba3N2.
3Ba + N2 ------> Ba3N2
A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.