The correct answer should be <span>b. cattle on rangeland
Point source pollution contributors are any pollution contributors that can be pinpointed to a single location, and dispersed cattle on a rangeland is not it. A a paper mill or a feed lot or a slaughter house can easily be pinpointed.</span>
B- black allele;
b- brown allele;
The parental cross is true-breeding because both the male and the female are homo zygotes, so: BBx bb
The F1 generation will be all black heterozygote: Bb
The F2 generation will be between mice of the F1 generation and they all have the same genotype:Bb xBb
In this cross it would result in:
1/4 of the plants being black homozygote-BB 25%
2/4 of the plants being black heterozygote- Bb- 50%
1/4 of the plants being brown homozygote- bb- 25%
answer: 25%+25%=50% are homozygotes
Answer:
Hydrolysis.
Explanation:
Maltose is produced by hydrolysis of starch, in the presence of amylase, can be detected by colorimetric assay. As per the assay of hydrolysis of starch we have concluded from the test of enzyme activity of amylase is that maltose being a reducing sugar which reacts and reduces the DNS (3,5-dinitrosalicylic acid) that is basically a pale yellow colored alkaline which results after some minutes into 3-amino,5-nitrosalicyclic acid which orange red colored alkaline after heating.
Answer:
All the F2 progeny with recessive traits would be males
Explanation: This is because the x-linked trait chromosomes are recessive, The F1 when crossed would contain females but when crossed again the F2 progeny with recessive traits would be males
