Answer and Explanation:
<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee
We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:
1) aa x AA
F1) 4/4=1 Aa
2) Bb x bb
F1) ½ bb
½ Bb
3) dd x Dd
F1) ½ dd
½ Dd
4) Ee x Ee
F1) ¼ EE
2/4 = ½ Ee
¼ ee
So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:
1 Aa x ½ Bb x ½ Dd x ½ Ee = 1/8 AaBbDdEe
Answer:
Meiosis is a reduction division of diploid cells.(2n) Chromosomes numbers are reduced with each successive division stages of meiosis 1 and 2, to haploid(n).
Cats have 38 diploid somatic (body)chromosome (2n) in the somatic cells and are reduced to 19 new varied haploid cells (n) of chromosomes in the gametes.
In cats, as in other mammals, during spermatogenesis in (seminiferous tublule of testis) and oegensis(in the ovaries);<u>meiotic reduction division</u> reduced the diploid somatic chromosomes to haploid chromosomes in sex gametes.
Therefore 38 chromosomes will be in the somatic chromosomes, while the sex gametes, with double-helical molecules of DNA, at the end of meiosis II will have 19 chromosomes, half of the somatic chromosomes.
Explanation:
The smooth ER sends the lipids to the golgi which in turn sends them elsewhere in the cell or outside of the cell.
Answer:
the answer is c. it has both DNA and RNA
