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faust18 [17]
3 years ago
13

Which of the following equations represent redox reactions? For each redox reaction, determine which atom is oxidized and which

is reduced, and identify the oxidizing agent and the reducing agent.
a. MgO(s) + H2CO3(aq) → MgCO3(s) + H2O(l)
b. 2KNO3(s) → 2KNO2(s) + O2(g)
c. H2(g) + CuO(s) → Cu(s) + H2O(l)
d. NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
e. H2(g) + Cl2(g) → 2HCl(g)
f. SO3(g) + H2O(l) → H2SO4(aq)
Chemistry
1 answer:
makkiz [27]3 years ago
4 0

Answer:

c. H2(g) + CuO(s) → Cu(s) + H2O(l)

e. H2(g) + Cl2(g) → 2HCl(g)

Explanation:

A redox reaction is a reaction that involves a changes in oxidation number of the species involved in the reaction.

The oxidizing agent experiences a decrease in oxidation number while the reducing agent experiences an increase in oxidation number.

For H2(g) + CuO(s) → Cu(s) + H2O(l)

Copper is reduced from +2 to 0 while hydrogen is oxidized from 0 to +2 Hence hydrogen is the reducing agent while copper is the oxidizing agent.

For H2(g) + Cl2(g) → 2HCl(g)

Chlorine is reduced from 0 to -1 while hydrogen is oxidized from 0 to +1. Hence chlorine is the oxidizing agent while hydrogen is the reducing agent.

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Answer:

5.8μg

Explanation:

According to the rate or decay law:

N/N₀ = exp(-λt)------------------------------- (1)

Where N = Current quantity,  μg

            N₀ = Original quantity, μg

             λ= Decay constant day⁻¹

              t =  time in days

Since the half life is 4.5 days, we can calculate the  λ from (1) by  substituting N/N₀ = 0.5

0.5 = exp (-4.5λ)

ln 0.5  = -4.5λ

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Substituting into (1)  we have :

N/N₀ = exp(-0.154t)----------------------------- (2)

To receive 5.0 μg of the nuclide with a delivery time of 24 hours or 1 day:

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Substituting into (2) we have

[5/N₀]   = exp (-0.154 x 1)

    5/N₀        = 0.8572

N₀  =  5/0.8572

     =    5.8329μg

    ≈     5.8μg

The Chemist must order 5.8μg  of 47-CaCO3

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