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Jlenok [28]
3 years ago
11

PLEASE ANSWER QUICKLY!

Chemistry
2 answers:
erica [24]3 years ago
7 0

Answer:

c

c

Explanation:

h3po4 + 12.81 - p40.10

prohojiy [21]3 years ago
5 0

<u>Answer:</u>

<em>A. 837 grams of H_3PO_4 are produced when 12.81 moles of water react with an excess of P_4O_{10}</em>

<em></em>

<u>Explanation:</u>

The balanced chemical equation is

P_4 O_10  + 6 H_2 O > 4 H_3 PO_4

Mole ratio of H_2 O:H_3 PO_4 is 6 : 4 or 3 : 2

As per the Equation

6 moles of water produces 4 moles of Phosphoric acid

So let us convert  

12.81 moles H_2 O to moles H_3 PO_4 by using mole ratio and then to mass H_3 PO_4 by  multiplying with molar mass H_3 PO_4

12.82 mol H_2 O \times \frac {(4mol H_3 PO_4)}{(6molH_2 O)} \times \frac {(98gH_3 PO_4)}{(1mol H_3 PO_4 )}

=837g H_3 PO_4 is produced

<u>Please note:  </u>

Molar mass is the mass of 1 mole of the substance and its unit is g/mol

We find the molar mass by adding the atomic mass of the atoms present in it.

For example H_3  PO_4 contains 3 atoms of H, 1 atom of P and 4 atoms of O

So the molar mass

=(3\times1.008)+(31\times1)+(4\times16)=98 g/mol

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2 years ago
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Benzoic acid, c6h5cooh, has a ka = 6.4 x 10-5. what is the concentration of h3o+ in a 0.5 m solution of benzoic acid? 3.2 x 10-5
FinnZ [79.3K]
The answer for this issue is: 
The chemical equation is: HBz + H2O <- - > H3O+ + Bz- 
Ka = 6.4X10^-5 = [H3O+][Bz-]/[HBz] 
Let x = [H3O+] = [Bz-], and [HBz] = 0.5 - x. 
Accept that x is little contrasted with 0.5 M. At that point, 
Ka = 6.4X10^-5 = x^2/0.5 
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3 0
3 years ago
When 0.49 g of a molecular compound was dissolved in 20.00 g of cyclohexane, the freezing point of the solution was lowered by 3
IRISSAK [1]

Answer: The molecular mass of this compound is 131 g/mol

Explanation:

Depression in freezing point:

\Delta T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

\Delta T_f = depression in freezing point  = 3.9^oC

k_f = freezing point constant  = 20.8^0C/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute = 0.49 g

w_1 = mass of solvent (cyclohexane) = 20.00 g

M_2 = molar mass of solute = ?

Now put all the given values in the above formula, we get:

(3.9)^oC=1\times (20.8^oC/m)\times \frac{(0.49g)\times 1000}{M_2\times (20.00g)}

M_2=131g/mol

Therefore, the molar mass of solute is 131 g/mol

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2 years ago
How do cells use lipids and carbohydrates?
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Answer:

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Explanation:

hope this helps!

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3 years ago
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