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Naddika [18.5K]
1 year ago
13

Select the equality for the following: 1 L is 1.06 QT

Chemistry
1 answer:
sattari [20]1 year ago
3 0

Answer

Third option 1 L = 1.06 qt

Explanation

The quart (symbol: qt) is a unit of volume, a liquid quart is equal to approximately 0.946353 liters and a dry quart is equal to approximately 1.101221 liters.

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Under the right conditions aluminum will react with chlorine to produce aluminum chloride.
salantis [7]

Answer:

m_{Al}=9.42gAl

Explanation:

Hello there!

In this case, according to the given chemical reaction:

2 Al + 3 Cl2 --> 2 AlCl3

Whereas there is a 2:3 mole ratio of aluminum to chlorine; it will be possible for us to calculate the required grams of aluminum by using the equality 22.4 L = 1 mol, the aforementioned mole ratio and the atomic mass of aluminum (27.0 g/mol) to obtain:

m_{Al}=11.727LCl_2*\frac{1molCl_2}{22.4LCl_2}*\frac{2molAl}{3molCl_2}  *\frac{27.0gAl}{1molAl} \\\\m_{Al}=9.42gAl

Regards!

8 0
3 years ago
How many atoms does 2.0 moles of He represent
Rudiy27

We use the following formula to calculate the number of atoms:

n (mol) = N(number of atoms) / NA

N(He) = n(mol) · NA

N(He) = 2,0 moles · 6.02·1023 = 12.04·1023 atoms

6 0
4 years ago
A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and wa
timofeeve [1]
The answer you are looking for would be a colliod. Hope this helps have a great day!!

6 0
3 years ago
Read 2 more answers
Your apple juice has a molarity of 3.4 M and a volume of 0.895 litres. What does a student have to do to decrease the molarity t
Jlenok [28]

Answer:

4.285 L of water must be added.

Explanation:

Hello there!

In this case, for this dilution-like problems, we need to figure out the final volume of the resulting solution so that we would be able to obtain the correct volume of diluent (water) to be added. In such a way, we can obtain the final volume, V2, as shown below:

M_1V_1=M_2V_2\\\\V_2=\frac{M_1V_1}{M_2}

Thus, by plugging in the initial molarity, initial volume and final molarity (0.587 M) we obtain:

V_2=\frac{3.4M*0.895 L}{0.587M}\\\\V_2=5.18L

It means we need to add:

V_{H_2O} ^{added}=5.18L-0.895L=4.285L

Of diluent water.

Regards!

6 0
3 years ago
Question 1
nordsb [41]

#1 B

#2 C

#3 B

#4 A.

I Just did this


8 0
3 years ago
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