1. The pH of the solution is 1.36
2. The pH of the solution is 10.47
3. the concentration of [H₃O⁺] in the solution is 6.3×10⁻¹⁴ M
<h3>What is pH ? </h3>
This is simply a measure of the acidity / alkalinity of a solution.
The pH measures the hydrogen ion (hydronium ion) concentration while the poH measures the hydroxide ion concentration. It is expressed mathematically as
pH = –Log H₃O⁺
<h3>1. How to determine the pH</h3>
- [H₃O⁺] = 4.32×10⁻² M
- pH = ?
pH = –Log H₃O⁺
pH = –Log 4.32×10⁻²
pH = 1.36
<h3>2. How to determine the pH</h3>
- [H₃O⁺] = 3.4×10⁻¹¹ M
- pH = ?
pH = –Log H₃O⁺
pH = –Log 3.4×10⁻¹¹
pH = 10.47
<h3>3. How to determine the concentration of [H₃O⁺]</h3>
pH = –Log H₃O⁺
13.2 = –Log H₃O⁺
Multiply through by -1
-13.2 = Log H₃O⁺
Take the anti-log of -13.2
H₃O⁺ = anti-log (-13.2)
H₃O⁺ = 6.3×10⁻¹⁴ M
Learn more about pH:
brainly.com/question/3709867
#SPJ1
Answer:
Covalent
Explanation:
Using an electronegativity chart, such as the attached one, you see that Nitrogen (N) has an electronegativity value of 3.0. Because both molecules are the same, 3.0-3.0=0. Therefore, because the electronegativity value difference is 0, the bond must be covalent.
Answer:
0.5ppm
Explanation:
Step 1:
Data obtained from the question.
Volume of water = 2500L
Mas of Cu = 1.25 g
Step 2:
Determination of the concentration of Cu in g/L. This is illustrated below:
Volume of water = 2500L
Mas of Cu = 1.25 g
Conc. of Cu In g/L =?
Conc. g/L = Mass /volume
Conc. of Cu in g/L = 1.25/2500
Conc. of Cu in g/L = 5x10^–4 g/L
Step 3:
Conversion of the concentration of Cu in g/L to ppm. This is illustrated below
Recall:
1g/L = 1000mg/L
Therefore, 5x10^–4 g/L = 5x10^–4 x 1000 = 0.5mg/L
Now, we know that 1mg/L is equal to 1ppm.
Therefore, 0.5mg/L is equivalent to 0.5ppm
Explanation:
SOLID
Sodium hydroxide exists in the solid phase at room temperature. You would find it in the lab as hemispherical white solid pellets. The phase of a substance depends on temperature and pressure. As you heat a solid, it will melt and change to the liquid phase.
Answer:
ΔE = 150 J
Explanation:
From first law of thermodynamics, we know that;
ΔE = q + w
Where;
ΔE is change in internal energy
q is total amount of heat energy going in or coming out
w is total amount of work expended or received
From the question, the system receives 575 J of heat. Thus, q = +575 J
Also, we are told that the system delivered 425 J of work. Thus, w = -425 J since work was expended.
Thus;
ΔE = 575 + (-425)
ΔE = 575 - 425
ΔE = 150 J
