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topjm [15]
3 years ago
10

Somebody please help me I am leaving at 5:00

Mathematics
1 answer:
Marta_Voda [28]3 years ago
3 0
2. Less than 1 liter

3. Less than 1 liter

4. Less than 1 liter

5. More than 1 liter

6. Less than 1 liter

Glad I could help, and good luck!

AnonymousGiantsFan
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A ski lift is designed with a total load limit of 20,000 pounds. It claims a capacity of 100 persons. An expert in ski lifts thi
Yanka [14]

Answer:

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n values of a distribution, the mean is \mu \times n and the standard deviation is \sigma\sqrt{n}

An expert in ski lifts thinks that the weights of individuals using the lift have expected weight of 200 pounds and standard deviation of 30 pounds. 100 individuals.

This means that \mu = 200*100 = 20000, \sigma = 30\sqrt{100} = 300

If the expert is right, what is the probability that a random sample of 100 independent persons will cause an overload

Total load of more than 20,000 pounds, which is 1 subtracted by the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 20000}{300}

Z = 0

Z = 0 has a pvalue of 0.5

1 - 0.5 = 0.5

0.5 = 50% probability that a random sample of 100 independent persons will cause an overload

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3 years ago
The value of 7 in 375,081 is 7000
Morgarella [4.7K]
70,000 when a zero is in between you gonna count it
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3 years ago
Pleaseeee answer correctly <br> Will mark Brianliest !!! HELP !
Paha777 [63]

Answer: 11

The code would print 11 as x=x-4 basically sets x to what x was and subtracts it by 4 which means 15 was its previous value and it takes 4 away from it so it is now 11. Then because the loop condition is x=11 the loop condition has been met and will now go and display x.

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3 years ago
What is the equation of the graph shown?​
OlgaM077 [116]

<em>Greetings from Brasil...</em>

As we have a line, the function will be given by the expression:

F(X) = AX + B

where

<em>A = ΔY/ΔX</em>

<em>B = where the line intersects the Y axis</em>

Looking at the graph we have already concluded that

B = - 3

A = ΔY/ΔX

A = (5 - 3)/(4 - 3)     see attached picture

A = 2

So,

F(X) = AX + B

<h2>F(X) = 2X - 3</h2>

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