Answer:
fourth option
Step-by-step explanation:
the answer should be the fourth option.
hope it helped you there?
<u>Answer:</u>
-2
<u>Step-by-step explanation:</u>
We have been given a function f(x)=\frac{-2x}{x+1} and we are asked to find the horizontal asymptote of our given function.
Recalling the rules for a horizontal asymptote:
1. If the numerator and denominator have equal degree, the horizontal asymptote will be the ratio of the leading coefficients.
2. If the polynomial of denominator has larger degree than the numerator, then the horizontal asymptote will be the x-axis or y=0.
3. If the polynomial of numerator has larger degree than denominator, then the function has no horizontal asymptote.
Here, the numerator and denominator are of the same degree. So the horizontal asymptote will be the ratio of the coefficients.
Horizontal asymptote =
= -2
Answer:
hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to
Answer: v = 5v + 4u + 1.5sin(3t),
Step-by-step explanation:
u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1
v represents the "velocity function" i.e v = u'(t)
As v = u'(t)
<em>u' = v</em>
since <em>u' = v </em>
v' = u"
v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )
= 5v + 4u + 1.5sin(3t) ( noting that v = u' )
so v' = 5v + 4u + 1.5sin(3t)
d/dt
=
+
Given that u(1) = 1 and u'(1) = 2.5
since v = u'
v(1) = 2.5
note: the initial value for the vector valued function is given as
= ![\left[\begin{array}{ccc}1\\2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Yes I think it really is the correct answer
Y-2=5(x+3) is the the answer