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olchik [2.2K]
3 years ago
7

Jon and Jim are cutting a log Jon cut 1/5 of the log on one end while Jim cut 2/9 of the log on the other side.How much of the l

og is left
Mathematics
2 answers:
Mandarinka [93]3 years ago
8 0
26/45 Of The Log Is Remaining ..
Nuetrik [128]3 years ago
5 0
There is 26/45 of the log left.
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Replace ∗ with a monomial so that the derived equality will be an identity: (15y + ∗)2 = 225y2+12x3y+0.16x6
kobusy [5.1K]

Answer:

<u>∗ = 0.4x³</u>

Step-by-step explanation:

(15y + ∗)² = 225y²+12x³y+0.16x⁶

<u>Note:</u>

225y² = 15y * 15y = (15y)²

12x³y = 2 * 15y * 0.4x³

0.16x⁶ = 0.4x³ * 0.4x³ = (0.4x³)²

So, by factoring the right hand side:

225y²+12x³y+0.16x⁶ = (15y + 0.4x³)²

By comparing the left hand side with (15y + 0.4x³)²

<u>So, ∗ should be replaced with the monomial 0.4x³</u>

6 0
3 years ago
Please help my<br> home work is due tomorrow
bekas [8.4K]
Why is everything due tomorrow xD. Also im sorry but I dont understand this either.
5 0
3 years ago
Can someone help me with this,'<br><br><br> PLEASE?!?!
Citrus2011 [14]
I think that the number of times you drink all the water in your bottle is independent, because the number of liters you drink depends on how much there is.

Independent- the number of times you drink all the water in your bottle
Dependent- the number of liters you drink
8 0
3 years ago
Evaluate the expression: H - 7 for H = 22
Orlov [11]

Answer:

15

Step-by-step explanation:

H - 7

When H = 22, replace H with 22 in the equation.

22 - 7 = 15

7 0
3 years ago
Read 2 more answers
Blood pressure values are often reported to the nearest 5 mmHg (100, 105, 110, etc.). The actual blood pressure values for nine
Paladinen [302]

Answer:

a) 117.4

b) 117.9

c) Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

Step-by-step explanation:

We are given the following data set in the question:

108.6, 117.4, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

n = 9

a) Median of the reported blood pressure values

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.4, 120.0, 121.5, 123.2, 128.4

Median =

\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.4

b) New median of the reported values

Data: 108.6, 117.9, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.9, 120.0, 121.5, 123.2, 128.4

New Median =

\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.9

c) Since median is a position based descriptive statistics, a small change in values can bring a change in the median value as the order of the data may change.

Option A)  When there is rounding or grouping, the median can be highly sensitive to small change

7 0
3 years ago
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