A 0.0300 M NaCl solution was formed when 42.0 grams of NaCl was dissolved in enough water. What was the total volume of the solu
1 answer:
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Answer:
[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka
Explanation:
The reaction of dissociation of the benzoic acid in water is given by the following equation:
C₆H₅-COOH + H₂O ⇄ C₆H₅-COO⁻ + H₃O⁺ (1)
The dissociation constant of an acid is the measure of the strength of an acid:
HA ⇄ A⁻ + H⁺ (2)
(3)
<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA]. </em>
So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:
I hope it helps you!
The question is incomplete, here is the complete question:
A. (6.5-6.10)/3.19
B. (34.123 + 9.60) / (98.7654 - 9.249)
<u>Answer:</u>
<u>For A:</u> The answer becomes 0.1
<u>For B:</u> The answer becomes 0.4884
<u>Explanation:</u>
Significant figures are defined as the figures present in a number that expresses the magnitude of a quantity to a specific degree of accuracy.
Rules for the identification of significant figures:
- Digits from 1 to 9 are always significant and have infinite number of significant figures.
- All non-zero numbers are always significant. For example: 664, 6.64 and 66.4 all have three significant figures.
- All zeros between the integers are always significant. For example: 5018, 5.018 and 50.18 all have four significant figures.
- All zeros preceding the first integers are never significant. For example: 0.00058 has two significant figures.
- All zeros after the decimal point are always significant. For example: 2.500, 25.00 and 250.0 all have four significant figures.
- All zeroes used solely for spacing the decimal point are not significant. For example: 10000 has one significant figure.
<u>Rule applied for addition and subtraction:</u>
The least precise number present after the decimal point determines the number of significant figures in the answer.
<u>Rule applied for multiplication and division:</u>
In case of multiplication and division, the number of significant digits is taken from the value which has least precise significant digits
- <u>For A:</u> (6.5-6.10)/3.19
This a a problem of subtraction and division.
First, the subtraction is carried out.
Here, the least precise number after decimal was 1.
Here, the least precise number of significant digit is 1. So, the answer becomes 0.1
- <u>For B:</u> (34.123 + 9.60) / (98.7654 - 9.249)
This a a problem of subtraction, addition and division.
First, the subtraction and addition is carried out.
Here, the least precise number after decimal in addition are 2 and in subtraction are 3
Here, the least precise number of significant digit are 4. So, the answer becomes 0.4884