The work done depends upon the --------------applied and the -------------- produced
1 answer:
Answer:
The work done depends upon the <u> Force</u> applied and <u>Displacement</u> produced.
Explanation:
Definition: Work is said to be on a body only if a force acting on it causes a displacement in its direction .
In other words we can say it is the product of force and displacement
Formula:
Unit:
The unit of work is Joule.
So, work depends on the force applied and the displacement caused by the applied force.
If force is applied and there is no displacement, then work is 0 .
Example: Pushing a wall does no work.
Work is positive if force applied and displacement is in same direction.
Work is negative if force applied and displacement is in opposite direction.
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Answer:
a) If the reaction has a large negative ΔGo value, the reaction must reach equilibrium at a small extent of reaction value
d) ΔGo and ΔG have the same magnitude, they just have opposite signs.
Explanation:
The fraction of the total heat energy if a system that does useful work is known as Gibb's free energy (G) and the change from the initial to final state is designated by . It is observed that the values of
changes with experimental conditions such as temperature , pressure , concentration etc.
is the standard free energy change which is a balance of two natural tendencies of any system.
- Minimization of potential energy or enthalpic factor
Maximization of disorderliness or entropic factor
Mathematically; =
-
Thus; from above mentioned, the statements that are true about ΔG⁰ and ΔG are:
ΔG⁰ and ΔG can have different values, they don't even have to have the same sign
For a reaction that reaches equilibrium, the minimum value of free energy must be at the equilibrium point
If ΔG⁰ , measured at an extent of reaction = 0.5, is positive, the sign for ΔG when the extent of reaction = 0.80 is also positive.
while the false statements include:
a) If the reaction has a large negative ΔG⁰ value, the reaction must reach equilibrium at a small extent of reaction value
d) ΔG⁰ and ΔG have the same magnitude, they just have opposite signs.