Answer:
molar mass of methane CH4
= C + 4 H
= 12.0 + 4 x 1.008
= 12.0 + 4.032
= 16.042g/mol
7.31 x 10^25 molecules x 1 mole CH4 = 121.43 moles
6.02 x 10^23 CH4 molecules
121.43 moles CH4 are present.
Explanation:
not to certain if this is right or not.. but hope it helps!
The answer to your question is: Chemical Reaction.
D.4s this would be the answer because after eight electrons are added to the third orbital two have to be added to the fourth before more can be added to the third one. The third orbital can hold 18 electrons, but it first has to have eight, then two on the fourth orbital, then the rest of the ten can be added
The neutralization reaction goes according to the scheme
H⁺ + OH⁻ = H₂O
acid and base react, salt and water are formed
NaOH + HNO₃ = NaNO₃ + H₂O
2KOH + H₂SO₄ = K₂SO₄ + 2H₂O
