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3 years ago

Can someone pls help me

Mathematics

1 answer:

Virty [35]3 years ago

8 0

Answer:

The answer is 56+7y

Step-by-step explanation:

7*8=56

7*y=7y

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Can someone please help me I posted this multiple times but no one answers pls help me quick

mario62 [17]

You would have to make 465=1550-7 1/2 x and find x
Subtract 1550 from both sides
-1085=-7 1/2x
Divide -7 1/2 on both sides
And the answer is 144 2/3
Sorry about ur bad luck

6 0

2 years ago

Which of the following constants can be added to x2 + x to form a perfect square trinomial?

solmaris [256]

The constant should be added to form a perfect square trinomial will be 1/4. Then the correct option is D.

<h3>What is a quadratic equation?</h3>

It's a polynomial with a value of zero. There exist polynomials of variable power 2, 1, and 0 terms. A quadratic equation is an equation with one statement in which the degree of the parameter is a maximum of 2.

The expression is x² + x.

Then the constant should be added to form a perfect square trinomial.

Then the constant will be

The square of the half of the coefficient of the variable x is to be added to make a perfect square.

Then the constant will be 1/4.

Then the perfect square will be

$\rm \rightarrow x^2 + x + \dfrac{1}{4}\\\\\\\rightarrow x^2 + 2 \times \dfrac{1}{2} x + \left (\dfrac{1}{2} \right )^2\\\\\\\rightarrow \left (x + \dfrac{1}{2} \right)^2$

More about the quadratic equation link is given below.

brainly.com/question/2263981

#SPJ1

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2 years ago

Can someone help me please

Ipatiy [6.2K]

The price of the shoes times .06 will give you the abswer

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3 years ago

It takes 52 minutes for 5 people to paint 5 walls.

Papessa [141]

i think its twenty hours.....but dont take my word on it im not 100% on it

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3 years ago

[20 pts] evaluate the logarithm log(6)1/36, show work pls!

Delvig [45]

Answer:

$\large\boxed{\log_6\dfrac{1}{36}=-2}$

Step-by-step explanation:

$\text{We know:}\\\\\log_ab=c\iff a^c=b\\\\\log_6\dfrac{1}{36}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_636^{-1}=\log_6(6^2)^{-1}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\log_66^{(2)(-1)}=\log_66^{-2}\qquad\text{use}\log_ab^n=n\log_ab\\\\=-2\log_66\qquad\text{use}\ \log_aa=1\\\\=-2(1)=-2$

$\log_6\dfrac{1}{36}=-2\ \text{because}\ 6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}$

8 0

3 years ago