Question

Find the height of an equilateral triangle with side length 8.

Answer 1

Answer:

U need to just do

$\sqrt{3 \div 4} a {}^{2}$

Answer 2

Answer:

4$\sqrt{5}$

Step-by-step explanation:

The segment from a vertex to the side opposite is a perpendicular bisector.

The equilateral Δ is divided into 2 right triangles with legs 8 and 4

let height be h, then using Pythagoras' identity

h² = 4² + 8² = 16 + 64 = 80 ( take the square root of both sides )

h = $\sqrt{80}$ = 4$\sqrt{5}$ ← exact value