Answer:
x=3
Step-by-step explanation:
Answer:
1/7
Step-by-step explanation:
If one child was born on a Monday, then we don't have to consider that when solving the question, as it asks if both children were born on a Monday.
Thus, we only need to find the probability that the second child is born on a Monday. Since there are 7 days in a week and equally likely that the child is born on any day, then the probability of the child being born on a Monday would be 1/7.
1. $9500 because 10*950=9500
2. $95 because 950/10=95
( can explain further )
Answer:
20.508%
Step-by-step explanation:
1/2 chance for one free throw.
1/2*4/10=4/20=1/5
Therefore, 20.508%
A= 3
b= 4
=3.14(a^2 + ab)
substitute the given a & b values in expression
=3.14((3)^2 + (3*4))
multiply inside parentheses
=3.14(9 + 12)
add inside parentheses
=3.14(21)
multiply
=65.94
ANSWER: 65.94
Hope this helps! :)
