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svet-max [94.6K]
3 years ago
12

1" title="9 \frac{3}{10 } + 7 \frac{1}{5} = " alt="9 \frac{3}{10 } + 7 \frac{1}{5} = " align="absmiddle" class="latex-formula">
what is the answer​
Mathematics
1 answer:
julsineya [31]3 years ago
5 0

Answer:

16\frac{1}{2}

Step-by-step explanation:

<em>Hey there !!!!</em>

there are many ways to solve this problem. but the most common way is to add the the whole number than add the fraction part:

if we solve it :

Rewriting our equation with parts separated

9+\frac{3}{10} + 7+\frac{1}{5}

Solving the whole number parts

9+7=16

Solving the fraction parts

\frac{3}{10}+\frac{1}{5} = ?

Find the LCD of \frac{3}{10} and \frac{1}{5} and rewrite to solve with the equivalent fractions.

LCD = 10

\frac{3}{10}+\frac{2}{10}=\frac{5}{10}

Reducing the fraction part, \frac{5}{10}

\frac{5}{10}=\frac{1}{2}

Combining the whole and fraction parts

16+\frac{1}{2} = 16\frac{1}{2}

have a wonderfulday

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Answer:

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

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Now,using Baye's theorem, we can find an expression for P(A|W)

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Plugging in relevant values, we have;

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Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

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Step-by-step explanation:

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The unit rate of the proportional relationship y = 3x is 3

<h3>How to determine the unit rate?</h3>

The proportional relationship is given as:

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For a proportional relationship y/x = k;

The unit rate is 3

This means that the unit rate of the proportional relationship y = 3x is 3

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Step-by-step explanation:

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