1.g(f(x)) = g(x^3 - 27)(x)
=x^3 - 27 -3
=x^3 -30
Matched with letter A.
2.f(x^2(x))= (x^3 - 27)^2
=(x^3 - 27)(x^3 - 27)
=x^6 - 54x^3 + 729
Matched with letter C
3. f(g(x))= f(x - 3)(x)
=(x - 3)^3 - 27
=[(x - 3)(x - 3)(x - 3)]-27
=x^3- 9^2+ 27x- 54
Matched with letter B.
4. (f(x))2 = (x^3 - 27)^2
=(x^3 - 27)(x^3 - 27)
=x^6 - 54x^3 + 729
Matched with letter C
Answer:
[6 12 2]
[0 0 0]
[0 6 2]
Step-by-step explanation:
Answer: False.
Step-by-step explanation:
There does not exist a "quarter circle" as a circle with a radius of 4 units, the only notable circle that does exist is the unit circle, that is the circle where the radius is equal to 1, represented by the equatin x^2 + y^2 = 1
The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.
So the statement is false
