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tankabanditka [31]
3 years ago
13

How can we use a number line to help calculate elapsed time

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0
I’m not 100% sure but i think by what i learned that you would use a number line to measure to the number than the closest number of the time your looking for would be looking for.
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Helpppp please
Doss [256]

Answer:

Pppppppppppppppppppppppppp

6 0
3 years ago
Throughout Lewis Carroll's book, Alice's Adventures in Wonderland, Alice's size changes. Her normal height is about 50 inches ta
alexandr402 [8]

Answer:

The answer is 75 inches.

Step-by-step explanation:

If Alice is 10 inches, she is 2/3 as tall as the door. At her regular height, to be 2/3 as tall as the door the door would have to be 75 inches high.

6 0
3 years ago
which geometric series represents 0.4444... as a fraction? a) 1/4, 1/40, 1/400, 1/4,000 b) 1/40, 1/400, 1/4,000, 1/40,000 c) 4/1
xenn [34]

Answer: \frac{4}{10}+\frac{4}{100}+\frac{4}{1,000}+\frac{4}{10,000}


Step-by-step explanation:

The given geometric series are:

a)\frac{1}{4}+\frac{1}{40}+\frac{1}{400}+\frac{1}{4,000}

on simplifying in decimals, we get

0.25+0.025+0.0025+0.00025=0.27775\neq0.4444

b) \frac{1}{40}+\frac{1}{400}+\frac{1}{4,000}+\frac{1}{40,000}

on simplifying in decimals, we get

0.025+0.0025+0.00025+0.000025=0.027775\neq0.4444

c)\frac{4}{10}+\frac{4}{100}+\frac{4}{1,000}+\frac{4}{10,000}

on simplifying in decimals, we get

0.4+0.04+0.004+0.0004=0.4444

Thus, this geometric series represent 0.4444.

d)\frac{1}{10}+\frac{1}{100}+\frac{1}{1,000}+\frac{1}{10,000}

on simplifying in decimals, we get

0.1+0.01+0.001+0.0001=0.1111\ \neq0.4444

7 0
4 years ago
Read 2 more answers
6) Which expressions are equivalent to 12x + 36y? Choose ALL that apply.
love history [14]

the 1st one

third one

fourth one

the last one

each of the equation has one of the common factor out

7 0
3 years ago
Read 2 more answers
What is the equivalent faction to 2/5
AysviL [449]
There are multiple answers, here are some.

4/10
8/15

and so on and so forth, to find these, just multiply each by two, three, and so on and so forth to find more.

Hope this helps!
8 0
3 years ago
Read 2 more answers
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