For this case we have the following transformation:
Using the transformation we have that the image is:
Therefore, making use of this information, we can find the coordinates of the pre-image
We have then:
From here, we clear x:
On the other hand we have:
From here, we clear y:
The coordinates of the pre-image is:
Answer:
A point that is the pre-image is:
Answer:
Y = (x + 3)(x - 4)(x + 1)^2
Y = (x^2 - x - 12)(x^2 + 2x + 1)
Y = x^4 + 2x^3 + x^2 - x^3 - 2x^2 - x - 12x^2 - 24x - 12
Y = x^4 + x^3 - 13x^2 - 25x - 12
Answer:
x^2 + 4x * (3 - sqrt(x)) - 2(5 + sqrt(x))
Step-by-step explanation:
Firstly let us split this up, we need to first work out what g(h(x)) is:
h(x) = Sqrt(x) so g(h(x)) = g(sqrt(x)) = sqrt(x) - 2
Now to work out f(g(h(x))) = f(sqrt(x) - 2) = (sqrt(x) - 2)^4 + 6
= (sqrt(x) - 2) * (sqrt(x) - 2) * (sqrt(x) - 2) * (sqrt(x) - 2) - 6
= (x - 2 * sqrt(x) + 4) * (x - 2 * sqrt(x) + 4) - 6
= x^2 - 2x * sqrt(x) + 4x - 2x * sqrt(x) + 4x - 8 * sqrt(x) + 4x - 8 * sqrt(x) + 16 - 6
= x^2 - 4x * sqrt(x) + 12x - 16 * sqrt(x) + 10
= x^2 + 4x * (3 - sqrt(x)) - 2(5 + sqrt(x))
Answer:
Step-by-step explanation:
Given
i.e. first to fifth
Required
Determine number of selection
1st position = Any of the 30 students
2nd position = Any of the 29 students
3rd position = Any of the 28 students
4th position = Any of the 27 students
5th position = Any of the 26 students
Number of selection is then calculated as:
