times more stars are there in universe compared to human eye can see
<h3><u>
Solution:</u></h3>
Given that, conservative estimate of the number of stars in the universe is 
The average human can see about 3,000 stars at night with only their eyes
To find: Number of times more stars are there in the universe, compared to the stars a human can see
Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see
Then from given statement,
<em><u>Substituting given values we get,</u></em>
Thus times more stars are there in universe compared to human eye can see
Answer:
ΔCFE is a right triangle
ΔBEC is an acute triangle
ΔBFG is an equilateral triangle
ΔGAF is an obtuse isosceles triangle
20y+30x=1000 divide 20 on each side to st the y alone.
y+30x=50 next put it in slope intercept form
y=30x+50 I don't know if this was te answer you were looking for but I hope it is
Answer:
g(x) - f(x) = -14x - 3
Step-by-step explanation:
We need to subtract the function f(x) = 9x + 4 from the function g(x) = -5 + 1. Rewriting these two functions in columns, we get
g(x)= -5x+1
- f(x) = -(9x+4) Note: Use parentheses as shown here.
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g(x) - f(x) = -14x - 3
