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attashe74 [19]
3 years ago
12

What is the domain of the function shown in the graph below?

Mathematics
2 answers:
Anika [276]3 years ago
7 0

Answer:

All numbers except 1

Step-by-step explanation:

The graph has an asymptote at 1.

So the function will grow toward but without reaching it.

The equation of the asymptote is x=1

So the domain is all real numbers except 1.

olasank [31]3 years ago
3 0
The domain is all real numbers except for 1
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If a is a negative number, then a(1/a) is equal to -1. If a is a negative number and b is a negative number, then product ab is
Firdavs [7]

Both claims are false. In fact, a and \frac{1}{a} are one the multiplicative inverse of the other. This means, by definition of multiplicative inverse, that

a \cdot \dfrac{1}{a} = 1 \quad\forall a \in \mathbb{R}

So, it doesn't matter if a is positive or negative: the multiplication of one number and its inverse will always be 1: for example,

(-2) \cdot \dfrac{1}{-2} = \dfrac{-2}{-2} = 1

Similarly, when you multiply two number, the sign of the product depends on the sign of the factors as follows:

  • (+) \cdot (+) = (+)
  • (+) \cdot (-) = (-)
  • (-) \cdot (+) = (-)
  • (-) \cdot (-) = (+)

So, the multiplication of two negative numbers is a positive number.

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3 years ago
The value of a house depreciates by 8% per year. Work out the current value of a house bought 2 years ago for £180000
Diano4ka-milaya [45]

₤ 152352

depreciation factor = 100 - 8 = 92% = 0.92

current value = ₤ 180000 × (0.92)² = ₤ 152352


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3 years ago
What is one disadvantage of a trade school education over a four-year college?
nekit [7.7K]

Answer:

answer the cost will be higher

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2 years ago
PLEASE HELP<br><br>divide. (3x-2)(x-4)-(x-4)(6-5x)<br>/(4-x)(8x-1)​
8_murik_8 [283]

Answer:

x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

Step-by-step explanation:

Solve for x:

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = 0

Simplify and substitute y = 4 - x.

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = -434 + 257 (4 - x) - 37 (4 - x)^2

= -37 y^2 + 257 y - 434:

-37 y^2 + 257 y - 434 = 0

Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Substitute back for y = 4 - x:

4 - x = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Subtract 4 from both sides:

-x = sqrt(1817)/74 - 39/74 or y - 257/74 = -sqrt(1817)/74

Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

Answer:  x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

7 0
3 years ago
Write the expression 3m - 4n - 8 as a sum
vlada-n [284]
3m - 4n - 8 = 3m + (-4n) + (-8)

The trms of the expression: 3m; -4n; -8
8 0
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