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In-s [12.5K]
3 years ago
9

Group one elements, like hydrogen, will bond with what other group to make a full outer shell? *

Chemistry
1 answer:
dsp733 years ago
4 0

Answer:

D. Group seven

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I have an unknown volume of gas at a pressure of 0.5 atm and a temperature of 325k if I raise the pressure to 1.2 atm, decrease
Nimfa-mama [501]
Use the Equation of Clapeyron:

\frac{P_1.V_1}{T_1}=\frac{P_2.V_2}{T_2}\\
\\
\frac{0.5V_1}{235}=\frac{1.2*48}{320}\\
\\
320*0.5V_1=235*1.2*48\\
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V_1=\frac{235*1.2*48}{320*0.5}=84.5 liters
7 0
3 years ago
Why does water dissolve sugar ? Explain your answer !
Marina CMI [18]
The sugar is a solvent. It's particles will break it down in the water
7 0
4 years ago
Electrical charge may be rapidly moved from one body to another by means of a(n)
Snowcat [4.5K]
<span>Conductor, and there you go, i hope this helped but if its wrong, i am extremly sorry</span>
5 0
3 years ago
Read 2 more answers
Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.
bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr <em>(1)</em>

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = <u><em>181,66 kJ/mol</em></u>

<u><em /></u>

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = <em><u>0,216 kJ/Kmol</u></em>

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ <em>4. +117,1 kJ/mol</em>

<em></em>

I hope it helps!

5 0
3 years ago
What reaction will take place if h2o is added to a mixture of nanh2/nh3? draw the products of the reaction (without sodium ion)?
Maru [420]

When sodium amide i.e.NaNH_{2} reacts with water i.e. H_{2}O results in the formation of sodium hydroxide i.e. NaOH and ammonia NH_{3}.

The chemical reaction is given by:

NaNH_{2}+H_{2}O\rightarrow NH_{3}+NaOH

Now, when ammonia i.e.NH_{3} reacts with water results in the formation of ammonium hydroxide i.e. NH_{4}OH

The chemical reaction is given by:

NH_{3}+H_{2}O\rightarrow NH_4OH

Thus, the products of the above reactions are ammonia and ammonium hydroxide (without sodium ion).

The structures of the products are shown in figure (1): ammonium hydroxide and figure (2) ammonia.


8 0
3 years ago
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