Given that the <em>length</em> ratio between the radii of the two circles is (2 · x) / (5 · y). The ratio of the areas of the two circles is (4 · x²) / (25 · y²).
<h3>What is the area ratio of two circles?</h3>
According to the statement we know that the radius ratio between two circles. Given that the area of the circle is directly proportional to the square of its radius, then the <em>area</em> ratio is shown below:
A ∝ r²
A = k · r²
A' · r² = A · r'²
A' / A = r'² / r²
A' / A = (r' / r)²
A' / A = [(2 · x) / (5 · y)]²
A' / A = (4 · x²) / (25 · y²)
Given that the <em>length</em> ratio between the radii of the two circles is (2 · x) / (5 · y). The ratio of the areas of the two circles is (4 · x²) / (25 · y²).
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Right triangles add up to 180 degrees and one of the angles is 90
The y-intercept of the line should be 7
Set up two equations
T = how tall
W = how wide.
T = W + 25 is the first equation
5
×
{
2
(
T
+
10
)
}
+
5
×
(
2
×
W
)
=
1350
This equation is the total height adding 5 for the top border and 5 for the bottom border. Then multiplying the total height by the width of the border 5, time 2 because there are two sides that are tall Then adding 5 times two widths.
An isosceles triangle is when 2 angles are the same measure. an triangles angle equal to 180 degrees. therefore angle A is 80 degrees as well as angle B equals 80 degrees. since the angles of a triangle equal to 180 you subtract the two known angles to find angle C. So 180-80-80 which equals to 20.
Therefore angle C=20 degrees
