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2 years ago

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The measure of an angle is 12 degrees. what is the measure of its supplement

1 answer:

Nana76 [90]2 years ago

5 0

Since the measure of an angle is 12 degrees less than the measure of its supplement, then x=180-x-12 or 2x=168 or x=84 and 180-x=96. Step 4. ANSWER: The angle is 84 degrees and its supplementary angle is 96 degrees.

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when atc has not imposed any climb or descent restrictions and aircraft are within 1,000 feet of assigned altitude, pilots shoul

ziro4ka [17]

In the absence of ATC restriction on climb or descent, and aircraft are within 1,000 feet of assigned altitude. pilots should attempt to both climb and descend at a rate of between 500 fpm and 15000 fpm. (Option A)

An Air Traffic Controller (ATC) clearance refers to an authorization by ATC for the purpose of preventing known aircraft collision. The rate of climb or descend expected by ATV is when an aircraft is within 1000 feet of assigned altitude, descend, or climb at an optimum rate consistent with the operating characteristics of the aircraft to 1,000 feet above or below the assigned altitude, and then attempt to descend or climb at a rate of between 500 and 1,500 fpm until the assigned altitude is reached.

Learn more about Air Traffic Controller (ATC):

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1 year ago

3 more than a number is greater than 27

maw [93]

Answer:

9 because 27 divided by 3 is 9

6 0

3 years ago

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A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d

nikitadnepr [17]

Answer:

a) k=2.08 1/hour

b) The exponential growth model can be written as:

$P(t)=Ce^{kt}$

c) 977,435,644 cells

d) 2.033 billions cells per hour.

e) 2.81 hours.

Step-by-step explanation:

We have a model of exponential growth.

We know that the population duplicates every 20 minutes (t=0.33).

The initial population is P(t=0)=58.

The exponential growth model can be written as:

$P(t)=Ce^{kt}$

For t=0, we have:

$P(0)=Ce^0=C=58$

If we use the duplication time, we have:

$P(t+0.33)=2P(t)\\\\58e^{k(t+0.33)}=2\cdot58e^{kt}\\\\e^{0.33k}=2\\\\0.33k=ln(2)\\\\k=ln(2)/0.33=2.08$

Then, we have the model as:

$P(t)=58e^{2.08t}$

The relative growth rate (RGR) is defined, if P is the population and t the time, as:

$RGR=\dfrac{1}{P}\dfrac{dP}{dt}=k$

In this case, the RGR is k=2.08 1/h.

After 8 hours, we will have:

$P(8)=58e^{2.08\cdot8}=58e^{16.64}=58\cdot 16,852,338= 977,435,644$

The rate of growth can be calculated as dP/dt and is:

$dP/dt=58[2.08\cdot e^{2.08t}]=120.64e^2.08t=2.08P(t)$

For t=8, the rate of growth is:

$dP/dt(8)=2.08P(8)=2.08\cdot 977,435,644 = 2,033,066,140$

(2.033 billions cells per hour).

We can calculate when the population will reach 20,000 cells as:

$P(t)=20,000\\\\58e^{2.08t}=20,000\\\\e^{2.08t}=20,000/58\approx344.827\\\\2.08t=ln(344.827)\approx5.843\\\\t=5.843/2.08\approx2.81$

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3 years ago

Use substitution to solve the<br> following system of equations.<br> 8x + 3y = -22 AND y= -6x - 14

irinina [24]

This is the correct answer for the system of equations

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2 years ago

I WILL GIVE BRAINLIEST, AND THX

bazaltina [42]

$4 - (x + 2) < - 3(x + 4) \\ 4 - x - 2 < - 3x - 12 \\ 2 - x < - 3x - 14 \\ (2x < - 14) \div 2 \\ x < - 7$

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3 years ago

Read 2 more answers