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kifflom [539]
2 years ago
13

if alpha and beta are zeros of the polynomial x² - 6 X + k find k such that (alpha+beta)²-2alha beta =40​

Mathematics
1 answer:
lidiya [134]2 years ago
8 0

Answer:

k = - 2

Step-by-step explanation:

Given α and β are the zeros of x² - 6x + k = 0 , with

a = 1, b = - 6 and c = k , then

α + β = - \frac{b}{a} = - \frac{-6}{1} = 6

αβ = \frac{c}{a} = \frac{k}{1} = k

Then solving

(α + β)² - 2αβ = 40

6² - 2k = 40

36 - 2k = 40 ( subtract 36 from both sides )

- 2k = 4 ( divide both sides by - 2 )

k = - 2

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La medida del ángulo BOC pertenenciente al sistema de tres ángulos consecutivos es igual a 20°.

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Por la geometría Euclídea conocemos que un conjunto de ángulos cuando comparten entre cada par de ángulos vecinos comparten el mismo vértice y la misma semirrecta.

De acuerdo con el enunciado, tenemos las siguientes condiciones:

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Step-by-step explanation:

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