Question

Graph the following system of equation y= 3x + 11 y= -4x + 4

Answer 1

Answer:

These equations describe two lines that intersect at the point (-1, 8), one of them with a slope of 3, the other with a slope of -4.

Step-by-step explanation:

We can find the point where these two lines intersect by taking one of the equations, solving it for x, and substituting it into the other equation.

$y = -4x + 4\\-4x = y - 4\\4x = 4 - y\\x = 1 - \frac{y}{4} \\\\y = 3x + 11\\y = 3(1 - \frac{y}{4}) + 11\\y = 3 - \frac{3y}{4} + 11\\y + \frac{3y}{4} = 3 + 11\\\frac{4y}{4} + \frac{3y}{4} = 14\\\frac{7y}{4} = 14\\y = \frac{4}{7} * 14\\y = 4 * \frac{14}{7}\\y = 4 * 2\\y = 8$

Now we can plug that into our first equation to find x

$x = 1 - \frac{y}[4}\\x = 1 - \frac{8}[4}\\\\x = 1 - 2\\x = -1$

So these lines intersect at the point (-1, 8), one of them with a slope of 3, the other with a slope of -4

Answer 2

Answer:

Step-by-step explanation: