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rewona [7]
3 years ago
10

To remain a member of student council, a student must attend at least Three-fourths of the activities. Joey attends 15 of the ac

tivities and remains on the student council. Which inequality represents the total amount of student council activities, a?
Three-fourths a greater-than-or-equal-to 15
Three-fourths a less-than-or-equal-to 15
Three-fourths a less-than 15
Three-fourths a greater-than 15
Mathematics
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

Three-fourths a less-than-or-equal-to 15

Step-by-step explanation:

Hope this helps!

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The 2nd choice down in correct.
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If the mass is 10 the volume is
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If he mass is 10 then the volume is 100
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Name:
Triss [41]

Answer:

A

Step-by-step explanation:

The reason it's A is because to make the ratio 1:1 you need to have a whole number you can't have half a pencil or pen, so what you need to do is add 22 and 96 and divide you should get 59, but if you add 23 to 96 and divide you get 59.5 and you can't have half a pencil (you can but that's not what were looking for). So in problems like this add and then divide by 2 and choose whole numbers because you can't have half in ratios cause that won't give the correct answer.

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3 years ago
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Can someone please tell me what the equation for this will be.
Papessa [141]

Answer:

y = 0.8x + 0.5

Step-by-step explanation:

First, find the slope using two pairs of values, (0.5, 0.9) and (0.75, 1.1):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1.1 - 0.9}{0.75 - 0.5} = \frac{0.2}{0.25} = 0.8

m = 0.8

Find y-intercept, b, by substituting x = 0.5, y = 0.9 and m = 0.8 into y = mx + b

Thus:

0.9 = (0.8)(0.5) + b

0.9 = 0.4 + b

0.9 - 0.4 = b

b = 0.5

To write the equation substitute m = 0.8, and b = 0.5 into y = mx + b.

Thus:

y = 0.8x + 0.5

7 0
3 years ago
1. Which of the following is equivalent to x5y2/xy2 when x ≠ 0 and y ≠ 0?
Aleonysh [2.5K]
Q1. The answer is <span>D. x4
</span>
Let's first rewrite the expression:
x⁵y²/xy² = x⁵/x * y²/y²

Using the rule xᵃ/xᵇ = x(ᵃ⁻ᵇ), we can write the expression as following:
x⁵y²/xy² = x⁵/x * y²/y² = x⁵⁻¹ * y²⁻² = x⁴ * y⁰ = x⁴ * 1 = x⁴

Thus, the correct answer is D.


Q2. The answer is <span>A. 5(5^3/2/5)^2
</span>
125 in the form of exponent is 5³.
125 = 5³
Now, let's calculate all choices. 
 
The rules we will use are:
xᵃ * xᵇ = x(ᵃ⁺ᵇ)
xᵃ/xᵇ = x(ᵃ⁻ᵇ)
(xᵃ)ᵇ = xᵃ*ᵇ

A. 5(5³/2/5)² = 5 * (5³ * 5/2)²
                      = 5 * (5³⁺¹/2)²
                      = 5 * (5⁴/2)²
                      = 5 * (5⁴)²/(2)²
                      = 5 * 5⁴*²/4
                      = 5 * 5⁸ / 4
                      = 5¹⁺⁸ / 4
                      = 5⁹/4
                      ≠ 5³ ≠ 125

B. (5³/5⁴)⁻³ = (5³⁻⁴)⁻³
                   = (5⁻¹)⁻³
                   = 5⁽⁻¹⁾*⁽⁻³⁾
                   = 5³
                   = 125

C. 5⁻²/5⁻⁵  = 5⁽⁻²⁾⁻⁽⁻⁵) 
                  = 5⁽⁻²⁾⁺⁵
                  = 5³
                  = 125<span>

D. 5(5</span>⁵/5³) = 5 * 5⁵⁻³
                  = 5 * 5²
                  = 5¹⁺²
                  = 5³
                  = 125

Therefore, the only expression that is not equal to 125 is A.


Q3. The answer is <span>63x5

Let's check all choices
</span>The rules we will use are:
xᵃ * xᵇ = x(ᵃ⁺ᵇ)
xᵃ/xᵇ = x(ᵃ⁻ᵇ)
(xᵃ)ᵇ = xᵃ*ᵇ

A. 6³<span>x 
</span>6³x/6x⁵ = 6³/6 * x/x⁵
             = 6³⁻¹ * x¹⁻⁵
             = 6²x⁻⁴
             = 36x⁻⁴
             ≠ 36<span>

B. 6</span>³x⁵ 
6³x⁵/6x⁵ = 6³/6 * x⁵/x⁵
              = 6³⁻¹ * x⁵⁻⁵
              = 6² * x⁰
<span>              = 36 * 1
              = 36

C. 6x</span>⁵<span> 
</span>6x⁵/6x⁵ = 1
             ≠ 36
<span>
D. 6</span>⁷x⁵
6⁷x⁵/6x⁵ = 6⁷/6 * x⁵/x⁵
              = 6⁷⁻¹ * x⁵⁻⁵
              = 6⁶ * x⁰
              = 46656 * 1
              ≠ 36

Therefore, the correct choice is B.


Q4. The answer is

We will use the rule: xᵃ/xᵇ = x(ᵃ⁻ᵇ)

5.4 x 10¹²/1.2 x 10³ = 5.4 / 1.2 x 10¹²/10³
                               = 4.5 x 10¹²⁻³
                               = 4.5 x 10⁹


Q5. The answer is B. <span>To subtract powers with the same base, divide the exponents

Some of the rules </span><span>regarding operations with exponents are:
</span>xᵃ/xᵇ = x(ᵃ⁻ᵇ) - choice A
xᵃ * xᵇ = x(ᵃ⁺ᵇ) - choice C
(xᵃ)ᵇ = xᵃ*ᵇ - choice D

Through the process of elimination, choice B is not true.
8 0
3 years ago
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