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rewona [7]
3 years ago
10

To remain a member of student council, a student must attend at least Three-fourths of the activities. Joey attends 15 of the ac

tivities and remains on the student council. Which inequality represents the total amount of student council activities, a?
Three-fourths a greater-than-or-equal-to 15
Three-fourths a less-than-or-equal-to 15
Three-fourths a less-than 15
Three-fourths a greater-than 15
Mathematics
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

Three-fourths a less-than-or-equal-to 15

Step-by-step explanation:

Hope this helps!

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A national grocery store chain designed a study to determine whether its customers would be interested in home delivery. The cha
SashulF [63]
The parameter of the study's population is the 80% of all customers who shopped in the chain's stores that were interested in the home delivery service.

Population parameter is defined as any summary number that describes the entire population. It can be an average or a percentage/

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5 0
3 years ago
Read 2 more answers
I really need this answer to be correct
Fed [463]
It is unchanged because the same number would still be in the middle and there would still be the same amount of numbers

if
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if
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The median is unchanged
4 0
3 years ago
beth is making the minimum wage of $7.25 per hour. her boss promises her a raise of 5% how much more per week will she make if s
Korvikt [17]

Answer:

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6 0
3 years ago
Subtract: 5 – 3 1⁄3 . A. 2 1⁄3 B. 2 2⁄3 C. 3 1⁄3 D. 1 2⁄3
katovenus [111]
I would say 2 1/3
hope this helps
5 0
3 years ago
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Consider the following pair of equations:
Bond [772]
So the equations are: 

y= 3x + 3

y= x- 1

By the transitive property, we know x-1= 3x+3 (Transitive property means if a= b, and b= c, shouldn't a = c if they both equal b?)

so, x- 1= 3x + 3.  Now we isolate x and solve:
        +1          +1
x= 3x+ 4
-x  -x

0 = 2x+ 4
-4        -4

-4 = 2x
/2    /2

x= -2

Now, you can plug that back in to find y:

y = x- 1
y= -2 -1
y= -3

Then plug them both in to make sure it is correct. :o)
6 0
3 years ago
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