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3 years ago

For the polynomial 17x2 – x: (3 marks)

Mathematics

1 answer:

Sladkaya [172]3 years ago

7 0

Answer:

See below

Step-by-step explanation:

Given polynomial is: $17x^2 - x$

a. Terms: $17x^2, \: \&\: - x$

b. 17 and - 1

c. Binomial or quadratic polynomial

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The school that Jennifer goes to is selling tickets to a play. On the first day of ticket sales the

sweet [91]

Answer:

Adult ticket = $11

Children ticket = $9

Step-by-step explanation:

Let the price of adult tickets be x and let the price of children's ticket be y

For the first day, the equation of sales can be put as

3x + 12y = 141..........1

For the second day, the equation of sales can be put as:

13x + 6y = 197............2

We then take these two equations together and solve simultaneously.

3x + 12y = 141.......1

13x + 6y = 197........2

Solving by elimination method, we Multiply through equation 1 by 13 and multiply through equation 2 by 3.

39x + 156y = 1833.........3

39x + 18y = 591..............4

Then subtract equation 4 from equation 3

138y =1242

y = 9

Substitute "y=9" into equation 1 to find x

3x + 12(9) =141

3x + 108 = 141

3x = 141 - 108

3x = 33

x = 11

Hence,

Price of adult ticket = $11

Price of children ticket = $9

6 0

4 years ago

Correct and best answer will get brainliest and full ratings.

tensa zangetsu [6.8K]

M = 3
b = 8.25

you'll plug those numbers into this equation
y = mx + b

y = 3x + 8.25

your answer is D

8 0

3 years ago

the sum of the perimeter of two squares is 40cm while the sum of the area is 58cm². Find length the side of the square.

tia_tia [17]

$a,\ b-the\ length\ of\ sides\\\\(1)\qquad4a+4b=40\qquad\text{divide both sides by 4}\\\\a+b=10\to a=10-b\\\\(2)\qquad a^2+b^2=58\\\\\text{Substitute}\ (1)\ \text{to}\ (2):\\\\(10-b)^2+b^2=58\qquad\text{Use}\ (x-y)^2=x^2-2xy+y^2\\\\10^2-2(10)(b)+b^2+b^2=58\\\\100-20b+2b^2=58\qquad\text{subtract 58 from both sides}\\\\42-20b+2b^2=0\\\\2b^2-20b+42=0\qquad\text{divide both sides by 2}\\\\b^2-10b+21=0\\\\b^2-7b-3b+21=0\\\\b(b-7)-3(b-7)=0\\\\(b-7)(b-3)=0\iff b-7=0\ \vee\ b-3=0\\\\\boxed{b=7\ \vee\ b=3}$

$\text{Put the values of b to }\ (1):\\\\for\ b=7\to a=10-7=3\\\\for\ b=3\to a=10-3=7\\\\Answer:\ \boxed{7cm\ and\ 3cm.}$

8 0

4 years ago

In a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2. Section 05.01 Ex

jasenka [17]

Answer:

95% confidence interval for the mean efficiency is [84.483 , 85.517].

Step-by-step explanation:

We are given that in a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard deviation was 2.

So, the pivotal quantity for 95% confidence interval for the population mean efficiency is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\mu$ = sample average efficiency = 85

$\sigma$ = sample standard deviation = 2

n = sample of motors = 60

$\mu$ = population mean efficiency

So, 95% confidence interval for the mean efficiency, $\mu$ is ;

P(-2.0009 < $t_5_9$ < 2.0009) = 0.95

P(-2.0009 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.0009 ) = 0.95

P( $-2.0009 \times {\frac{s}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.0009 \times {\frac{s}{\sqrt{n} }$ ) = 0.95

P( $\bar X -2.0009 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.0009 \times {\frac{s}{\sqrt{n} }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.0009 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.0009 \times {\frac{s}{\sqrt{n} }$ ]

= [ $85 -2.0009 \times {\frac{2}{\sqrt{60} }$ , $85 +2.0009 \times {\frac{2}{\sqrt{60} }$ ]

= [84.483 , 85.517]

Therefore, 95% confidence interval for the population mean efficiency is [84.483 , 85.517].

8 0

3 years ago

What is the value of x in the equation (3/4 + 5/8) x = 3/5

mr Goodwill [35]

Answer:

It is x=−92 .

Step-by-step explanation:

3 0

3 years ago