If you are given 608 grams of calcium phosphate Ca3(PO4)2, how many moles would you have? *
1 answer:
Answer:
You would have 1.96 moles.
Explanation:
You are given 608 grams of calcium phosphate Ca₃(PO₄)₂.
Molar mass (M) is the amount of mass that a substance contains in one mole. This substance can be an element or a compound.
Since the molar mass of the compound Ca₃(PO₄)₂ is 310 g / mole, and taking into account the definition of molar mass, you can apply the following rule of three: if 310 grams of Ca₃(PO₄)₂ are contained in 1 mole, 608 grams of the compound in how many moles are present?
moles= 1.96
<u><em>You would have 1.96 moles.</em></u>
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Answer:
56.8cm³
Explanation:
Given parameters:
Measured volume = 54.5cm³
Percentage error = 4.25%
Unknown:
Actual volume of the cylinder = ?
Solution:
The percentage error shows the amount of error introduced into a measurement.
We need to find out this amount of error from the data given.
Error = Percentage error x measured volume
Error = x 54.5 = ±2.32cm³
Since the error introduced = 2.32cm³
Actual volume of cylinder = measured volume ± Error
Since the percentage error quoted as higher 4.25%;
Actual volume = 54.5cm³ + 2.32cm³ = 56.8cm³