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3 years ago

What is the mass of 1.45 moles of silver sulfate?

Chemistry

2 answers:

Rina8888 [55]3 years ago

6 0

The answer is 449.5g

tatuchka [14]3 years ago

3 0

Answer:

449.5 g

Explanation:

Silver sulfate- Ag2SO4

M(Ag)=107 g/mol => M(Ag2)=214 g/mol

M(S)=32 g/mol

M(O)=16 g/mol => M(O4)=64 g/mol

M(Ag2SO4)=310 g/mol

n=1.45 mol

m(Ag2SO4)=M(Ag2SO4)*n=310 g/mol *1.45 mol= 449.5 g

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Explanation:

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3 years ago

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6 0

3 years ago

What is the volume of a balloon of gas at 842 mm Hg and -23° C, if its volume is 915 mL at a pressure of 1,170 mm Hg and a tempe

garik1379 [7]

Answer:
V₂ = 1070 mL or 1.07 L

Solution:

Data Given;
P₁ = 1170 mmHg

V₁ = 915 mL

T₁ = 24 °C + 273 K = 297 K

P₂ = 842 mmHg

V₂ = ?

T₂ = - 23 °C + 273 K = 250 K

According to Ideal gas equation,

P₁ V₁ / T₁ = P₂ V₂ / T₂

Solving for V₂,

V₂ = P₁ V₁ T₂ / P₂ T₁

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5 0

3 years ago

How many grams are in 11.9 moles of chromirum

faust18 [17]

Answer:

Explanation:

Method 1 proportion

1 mole of chromium is 52 grams

11.9 moles = x grams

1/11.9 = 52/x Cross multiply

x = 11.9 * 52

x = 618.8 grams

Now I have used an approximate mass for Chromium. The answer you get here is expected to reflect the weigth given on your periodic table Use that to get your answer. You should give a number very close to mine. Round to 3 places as in 619.

Method Two Formula

mols = given mass / molecular mass

11.9 = given mass / 51.9961 Multiply both sides by 51.9961

11.9 *51.9961 = given mass

given mass = 618.75

given mass = 619

3 0

3 years ago