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3 years ago

What is the mass of 1.45 moles of silver sulfate?

Chemistry

2 answers:

Rina8888 [55]3 years ago

6 0

The answer is 449.5g

tatuchka [14]3 years ago

3 0

Answer:

449.5 g

Explanation:

Silver sulfate- Ag2SO4

M(Ag)=107 g/mol => M(Ag2)=214 g/mol

M(S)=32 g/mol

M(O)=16 g/mol => M(O4)=64 g/mol

M(Ag2SO4)=310 g/mol

n=1.45 mol

m(Ag2SO4)=M(Ag2SO4)*n=310 g/mol *1.45 mol= 449.5 g

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Molecular compounds are capable of forming multiple covalent bonds. the compound below that contains a triple bond is:

alexira [117]

The answer is <u>CO(g).</u>

4 0

2 years ago

g When 2.50 g of methane (CH4) burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of combustion (in kJ) per mole

Anna [14]

Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

3 0

3 years ago

What is the (a) frequency and (b) wavelength (in nm) of a source of purple light at the edge of the visible light spectrum?

stiv31 [10]

Answer: a) $Frequency=666\times10^{12}Hz-789\times10^{12}Hz$

b) $Wavelength=380nm-450nm$

Explanation: Visible light is a form of electromagnetic wave.

Wavelength is defined as the distance between two successive crests of a wave. It is represented as symbol $\lambda$ .

Frequency is defined as the number of complete cycles happening per second. It is represented by the symbol $\nu$ .

Wavelength and Frequency follow inverse relation,

$\nu=\frac{c}{\lambda}$

where, c = speed of light = $3\times10^8m/s$

Wavelength and frequency of a wave is usually expressed in a range.

a) $\text{Frequency of visible light}=666\times10^{12}Hz-789\times10^{12}Hz$

b) $\text{Wavelength of visible light}=380nm-450nm$

7 0

3 years ago

Help me please :3 :3 :3 ;3

Alona [7]

I think the answer is C.

8 0

3 years ago

sulfate = SO4 -2 phosphate = PO4 -3 hydroxide = OH- sodium hydroxide aNa(OH)2 bNa(OH)3 cNa2OH 4NaOH

blsea [12.9K]

4. NaOH
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6 0

3 years ago